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Andrew [12]
3 years ago
9

How many Na ions are in 2.7 g of NaCl? Answer in units of ions.

Chemistry
1 answer:
Viefleur [7K]3 years ago
3 0

Answer:

2.778 * 10^{22}

Explanation:

Weight of NaCl is equal to sum of weight of one mole of sodium and one mole of chloride.

Mathematically, it can be represented as -

1 mol (Na) + 1 mol (Cl) = 23.0  + 35.5  = 58.5 g/mol

In 58.5 gram of NaCl, there is one mole of Na or 6.02 * 10^{23} ions

In one gram of NaCl, there will be

\frac{6.02 * 10^{23}}{58.5} sodium ions

In 2.7 grams of  NaCl, the number of sodium ions will be -

\frac{6.02 * 10^{23}}{58.5} * 2.7

2.778 * 10^{22}

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3 years ago
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Vinegar is a solution of acetic acid, CH3COOH, dissolved in water. A 5.54-g sample of vinegar was neutralized by 30.10 mL of 0.1
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Answer:

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Explanation:

Step 1: Data given

Mass of the sample = 5.54 grams

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Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles NaOH

Moles NaOH = volume * molarity

Moles NaOH = 0.03010 L * 0.100M

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Step 4: Calculate moles CH3COOH

For 1 mol NaOH we need 1 mol CH3COOH

For 0.00301 moles NaOH we nee 0.00301 moles CH3COOH

Step 5: Calculate mass CH3COOH

Mass CH3COOH = moles CH3COOH * molar mass CH3COOH

Mass CH3COOH = 0.00301 moles * 60.05 g/mol

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Step 6: Calculate percent by weight of acetic acid

Mass % = ( 0.1808 / 5.54 ) *100%

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Hey there,

Your answer would be

Coefficients are placed in front of the reactants and/or products

Hope this helps,

<h2>- <em>Mr. Helpful</em></h2>

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Answer:

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Explanation:

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