Answer:
d.It must show the reactants and products on the correct sides of
the reaction arrow
Explanation:
hope it helps
The structure of 1-methoxypropane is CH₃-CH₂-CH₂-OCH₃
I will label the carbons A-D from left to right.
A B C D
CH₃-CH₂-CH₂-OCH₃
In a proton NMR spectrum, we are looking at the chemical shifts of each unique hydrogen atom, and the splitting patterns tell us how many hydrogens are attached to the adjacent carbon. Therefore, the signal from the protons on carbon A will be split by the protons on carbon B, and the signal for protons on carbon A will have a splitting pattern equal to n+1, where n = number of hydrogens on the adjacent carbon.
Therefore, for the protons on carbon A, there are two neighbouring protons and these will give a splitting patter of 3 peaks, also known as a triplet.
Protons on carbon A: 2 adjacent protons result in a triplet signal.
Protons on carbon B: 5 adjacent protons result in a sextet signal.
Protons on carbon C: 2 adjacent protons result in a triplet signal.
Protons on carbon D: 0 adjacent protons result in a singlet signal.
The precaution to be taken while measuring the temperature of a liquid in a beaker is applying proper heat balance and taking all the required precautions.
- A beaker with an open top contains a sample of liquid. It exposes this sample to light.
- That liquid absorbs the light energy, turning it into heat energy. As a result, the liquid becomes warmer and evaporation is accelerated. As a result, there is less liquid in the beaker.
- Since it is well known that the surface temperature of a liquid, along with air movement above the liquid surface, is one of the dominant factors affecting evaporation, I want to measure the evaporation rate as a function of surface temperature.
- This can be done by applying a heat balance.
Learn more about heat balance at:
brainly.com/question/1292905
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Answer:
1/3
Explanation:
Pyruvate is produced by the glycolysis in cytoplasm. The oxidation of pyruvate takes place in mitochondrial matrix.
Pyruvate is converted to acetyl-CoA in the reaction given below:
Pyruvate + NAD⁺ + CoA-SH ⇒ acetyl-CoA + NADH + CO₂
1 molecule of carbon dioxide is eliminated from 1 molecule of pyruvate.
Also,
2 molecules of carbon dioxide is eliminated from 2 molecules of pyruvate (as glucose on glycolysis yields 2 molecules of pyruvate).
Also, acetyl-CoA further goes into the citric acid cycle and produces 2 molecules of carbon dioxide.
Thus pyruvate produces total 3 molecules of CO₂ and hence glucose produces 6 molecules of CO₂ (as glucose on glycolysis yields 2 molecules of pyruvate)
Thus,
<u>Fraction = 2/6 = 1/3</u>
Answer:
Percent yield = 90.9%
Explanation:
Given data:
Mass of CaCO₃ = 50.0 g
Mass of CO₂ produced = 20.0 g
Percent yield = ?
Solution:
Chemical equation:
CaCO₃ → CaO + CO₂
Number of moles of CaCO₃:
Number of moles = mass/molar mass
Number of moles = 50.0 g/ 100.1 g/mol
Number of moles = 0.5 mol
Now we will compare the moles of CO₂ with CaCO₃.
CaCO₃ : CO₂
1 : 1
0.5 : 0.5
Mass of CO₂: Theoretical yield
Mass = number of moles × molar mass
Mass = 0.5 mol × 44 g/mol
Mass = 22 g
Percent yield:
Percent yield = ( actual yield / theoretical yield ) × 100
Percent yield = (20.0 g/ 22.0 g) × 100
Percent yield = 0.909 × 100
Percent yield = 90.9%
