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KiRa [710]
3 years ago
10

Alternative energy sources

Chemistry
1 answer:
sammy [17]3 years ago
4 0

Answer:

Natural resources like crude oil or animal disposal(poop)

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Which of the following is a galvanic cell?
Gemiola [76]

Answer:

i think Aluminum (Al) oxidized, zinc(Zn) reduced

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3 years ago
Nuclear power plants produce energy using fission. One common fuel, uranium-235, produces energy through the fission reaction 23
Vikentia [17]

Answer:

mass of U-235  = 15.9 g (3 sig. figures)

Explanation:

1 atom can produce -------------------------> 3.20 x 10^-11 J energy

x atoms can produce ----------------------> 1.30 x 10^12 J energy

x = 1.30 x 10^12 / 3.20 x 10^-11

x = 4.06 x 10^22 atoms

1 mol ----------------------> 6.023 x 10^23 atoms

y mol ----------------------> 4.06 x 10^22 atoms

y = 0.0675 moles

mass of U-235 = 0.0675 x 235 = 15.8625

mass of U-235  = 15.9 g (3 sig. figures)

7 0
3 years ago
What do you notice about the elements on the reactant and product side of the equation
Levart [38]
There is the same overall number of atoms of each element on the reactants side as on the products side, they are simply rearranged. Also, mass is conserved as atoms cannot be created or destroyed by a chemical reaction.  
4 0
3 years ago
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When sodium carbonate is dissolved in water, it doesn’t dissociate, or break up, completely. There is always some sodium carbona
dusya [7]
It's a weak base because weak bases don't dissociate completely. If it did, then it would be a strong base.
7 0
3 years ago
A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The
AysviL [449]

Answer:- Heat lost by the metal is 279.45 cal.

Solution:- This type of problems are solved by using the concept, heat given = - heat taken

Metal temperature is decreasing from 45.00 degree C to 11.08 degree C. It means the heat is lost by the metal and this heat lost by metal is gained by water and the calorimeter to raise their temperature.

the equation we use is, q=mc\Delta T .

where, q is the heat energy, m is mass, c is specific heat and \Delta T is change in temperature.

Combined mass of calorimeter and water is 250.0 g and the specific heat is \frac{1.035cal}{g.^0C} .

\Delta T  for calorimeter and water (combined) = 11.08 - 10.00 = 1.08 degree C

\Delta T  for metal = 11.08 - 45.00 = -33.92 degree C

let's plug in the values in the above equation and calculate heat gained by combined system.

q=250.0g*\frac{1.035cal}{g.^0C}*1.08^0C

q = 279.45 cal

So, the heat lost by the metal is 279.45 cal.


3 0
4 years ago
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