All categories

3 years ago

Cell notation will list each half-reaction:

Chemistry

1 answer:

likoan [24]3 years ago

6 0

Answer:

on each side of the salt bridge, which is represented by a double vertical line

Explanation:

While writing a cell notation, the general convention is; anode || cathode. The anode and the cathode are separated by a double line. The anode is written on the lefthand side while the cathode is written on the righthand side.

The cell notation is a shorthand representation of a cell, hence any electrochemical cell can easily be produced based on its cell diagram.

You might be interested in

Lithium carbonate, li2co3, contains 18.8 % lithium and is used in the treatment of mental illnesses such as bipolar disorder. wh

masha68 [24]

Assuming that the percentage composition is on the basis of weight percentage, therefore the mass of lithium would simply be the product of the two, that is:
mass Lithium = 0.188 * 1.70 g
mass Lithium = 0.3196 g = 0.32 g

5 0

3 years ago

Sodium carbonate can be made by heating sodium bicarbonate: 2NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g) Given that ΔH° = 128.9 kJ/m

Ad libitum [116K]

Answer:

[tex]128^{o}C[/tex]minimum temperature will the reaction become spontaneous.

Explanation:

$\Delta G=\Delta H-T \Delta S$

From the given,

$\Delta G^{o}=33.1$

$\Delta H^{o}=128.9kJ/mol$

$Temperature\,change=25+273=98K$

$33.1=128.9-298 \Delta S$

$\Delta S=0.322kJ/mol.K$

$\Delta G=\Delta H-T \Delta S$

$0=128.9-T(0.322)=401K=218^{o}C$

Therefore, $128^{o}C$ minimum temperature will the reaction become spontaneous.

7 0

3 years ago

Phosgene, COCl2, gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide w

jek_recluse [69]

The question is incomplete, here is the complete question:

Phosgene, $COCl_2$ , gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide with chlorine:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

The value of $K_c$ for this reaction is 5.79 at 570 K. What are the equilibrium partial pressures of the three gases if a reaction vessel initially contains a mixture of the reactants in which $p_{CO}=p_{Cl_2}=0.265atm$ and $p_{COCl_2}=0.000atm$ ?

Answer: The equilibrium partial pressure of CO, $Cl_2\text{ and }COCl_2$ is 0.257 atm, 0.257 atm and 0.008 atm respectively.

Explanation:

The relation of $K_c\text{ and }K_p$ is given by:

$K_p=K_c(RT)^{\Delta n_g}$

$K_p$ = Equilibrium constant in terms of partial pressure

$K_c$ = Equilibrium constant in terms of concentration = 5.79

$\Delta n_g$ = Difference between gaseous moles on product side and reactant side = $n_{g,p}-n_{g,r}=1-2=-1$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

T = Temperature = 570 K

Putting values in above equation, we get:

$K_p=5.79\times (0.0821\times 570)^{-1}\\\\K_p=0.124$

We are given:

Initial partial pressure of CO = 0.265 atm

Initial partial pressure of chlorine gas = 0.265 atm

Initial partial pressure of phosgene = 0.00 atm

The given chemical equation follows:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial: 0.265 0.265

At eqllm: 0.265-x 0.265-x x

The expression of $K_p$ for above equation follows:

$K_p=\frac{p_{COCl_2}}{p_{CO}\times p_{Cl_2}}$

Putting values in above equation, we get:

$0.124=\frac{x}{(0.265-x)\times (0.265-x)}\\\\x=0.0082,8.59$

Neglecting the value of x = 8.59 because equilibrium partial pressure cannot be greater than initial pressure

So, the equilibrium partial pressure of CO = $(0.265-x)=(0.265-0.008)=0.257atm$

The equilibrium partial pressure of $Cl_2=(0.265-x)=(0.265-0.008)=0.257atm$

The equilibrium partial pressure of $COCl_2=x=0.008atm$

Hence, the equilibrium partial pressure of CO, $Cl_2\text{ and }COCl_2$ is 0.257 atm, 0.257 atm and 0.008 atm respectively.

6 0

3 years ago

A sample of argon has a volume of 5.0 dm^3 and the pressure is 0.92 atm.

Evgesh-ka [11]

Answer:

232.9K

Explanation:

V₁ = 5dm³

P₁ = 0.92atm

T₂ = 30°C

V₂ = 5.7L

P₂ = 800mmHg

Unknown:

T₁ = ?

Solution:

To solve this problem, we are going to apply the combined gas law which is fusion of the avogadro's law, boyle's law and charles's law.

Mathematically;

$\frac{P_{1}V_{1} }{T_{1} } = \frac{P_{2}V_{2} }{T_{2} }$

p, v and T are pressure, volume and temperature respetively

1 and 2 depicts the initial and final states.

We need to convert ;

temperature to K and pressure into atm

T₂ = 30°C = 273 + 30 = 303K

P₂ = 800mmHg;

760mmHg = 1 atm

800mmHg = $\frac{800}{760}$ = 1.05atm

Input the variables and solve;

$\frac{0.92 x 5}{T} = \frac{1.05 x 5.7}{303}$

T = 232.9K

5 0

3 years ago

Through what process do humans and animals get the energy they need?

xenn [34]

Answer:

C heat energy

Explanation:

8 0

3 years ago