How many grams of lactic acid are in 1 liter of lactic acid?

1 answer:

6 0

The question is missing the concentration of the lactic acid solution. You also need the molar mass of the lactic acid (or its molecular formula to calculate it)

For example, the question should read how many grams of lactic acid (C3H6O3) are in 1 liter of 0.5 M solution of lactic acid?

Now I can teach you how to calculate the mass in grams of lactic acid.

1) number of moles, n

M = n / V => n = M*V = 0.5 M * 1 l = 0.5 moles

2) molar mass of C3H6O3

C3H6O3: 3* 12g/mol + 6* 1g/mol + 3*16g/mol = 90 g/mol

3) mass in grams = number of moles * molar mass

mass in grams = 0.5 mol * 90 g/mol = 45 g

Answer: 45 g

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<h3>Explanation</h3>

Typically, the oxidation state of Pb in lead nitrate tend to be +2. In other words, Pb in lead nitrate tends to exist as $\text{Pb}^{2+}$ ions. The formula for a nitrate ion is ${\text{NO}_3}^{-}$ . The charge on each of the nitrate ion is -1. The charge on the two ions should balance. As a result, each $\text{Pb}^{2+}$ ion in lead nitrate would pair up with two ${\text{NO}_3}^{-}$ ions. The formula for lead nitrate will be $\text{Pb}({\text{NO}_3})_2$ . Each formula unit of lead nitrate will contain one $\text{Pb}^{2+}$ ion and two ${\text{NO}_3}^{-}$ ions.

The "III" in the name "chromium (III) nitrate" is a Roman Numeral. It indicates that the oxidation state of Cr in chromium (III) nitrate is +3. The Cr in that compound will exist as $\text{Cr}^{3+}$ . Similarly, each $\text{Cr}^{3+}$ will pair up with three ${\text{NO}_3}^{-}$ ions. The formula for chromium (III) nitrate will be $\text{Cr}(\text{NO}_3})_3$ . Each formula unit of chromium (III) nitrate will contain one ${\text{NO}_3}^{-}$ ion and three ${\text{NO}_3}^{-}$ ions.

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Answer: B. It’s a dilute strong base.

Explanation:

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3) Definition of dilute: it refers to a solution meaning that the substance is not pure and the concentration is low. Since, the solution the Ca(OH)₂ is 0.02 M means that it is dilute.

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