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geniusboy [140]
3 years ago
12

How many grams of lactic acid are in 1 liter of lactic acid?

Chemistry
1 answer:
Anastaziya [24]3 years ago
6 0
The question is missing the concentration of the lactic acid solution. You also need the molar mass of the lactic acid (or its molecular formula to calculate it)

For example, the question should read how many grams of lactic acid (C3H6O3) are in 1 liter of 0.5 M solution of lactic acid?

Now I can teach you how to calculate the mass in grams of lactic acid.

1) number of moles, n

M = n / V => n = M*V = 0.5 M * 1 l = 0.5 moles

2) molar mass of C3H6O3

C3H6O3: 3* 12g/mol + 6* 1g/mol + 3*16g/mol = 90 g/mol

3) mass in grams = number of moles * molar mass

mass in grams = 0.5 mol * 90 g/mol = 45 g

Answer: 45 g
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An orgo lab student named Bob wanted to synthesize an isoamyl acetate ester because it smells like bananas and he really likes t
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Answer:

The answer is "11.07 g".

Explanation:

Isoamyl alcohol is a reagent restriction

Isoamyl alcohol Moles: 

= \frac{7.5}{88.15} \\\\ =0.085

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Isoamyl acetate grams:

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3 0
3 years ago
Why is hydrogen placed with the elements in group 1a??
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Because it has atomic no. = 1 (according to modern periidic table)
5 0
4 years ago
What is the type of mutation represented by the amino acid sequence below?
Ilia_Sergeevich [38]

Answer:

Substitution mutation

Explanation:

A substitution mutation is a type of mutation in which one or more nucleotide base is replaced by another in a sequence. This will result in the replacement of one or more amino acid in the amino acid sequence.

This is the case in this question where the original amino acid sequence was given as: Leucine – Alanine – Glycine – Leucine. After mutation, the following mutated sequence was produced: Leucine – Alanine – Valine – Leucine.

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6 0
3 years ago
Mercury (Hg) poisoning is a debilitating disease that is often fatal. In the human body, mercury reacts with essential enzymes l
alisha [4.7K]

Answer:

6 x 10⁵ kg Hg

Explanation:

The mass of mercury in the entire lake is found by multiplying the concentration of the mercury by the volume of the lake.

The volume of the lake is calculated in cubic feet:

V = (SA)x(depth) = (100mi²)(5280ft/mi)² x (20ft) = 5.57568 x 10¹⁰ ft³

Cubic feet are then converted to mL (1cm³=1mL)

(5.57568 x 10¹⁰ ft³) x (12in/ft)³ x (2.54cm/in)³ = 1.578856752 x 10¹⁵ mL

The mass of mercury is then found:

m = CV = (0.4μg/mL)(1g/10⁶μg)(1kg/1000g) x (1.578856752 x 10¹⁵ mL) = 6 x 10⁵ kg Hg

3 0
3 years ago
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