3 years ago

A truck moves 30 km West, and then 40 km North, and then travels in a straight path back to its starting

Physics

1 answer:

SpyIntel [72]3 years ago

7 0

Distance = (30+40+50) = 120 km

It's back where it started, so displacement = zero

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A 100 N force is applied to a box at an angle of 60° to the

Anarel [89]

Answer: lift force = 100sin60 = 86.6 N

pull force = 100sin60 = 50.0 N

Explanation:

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2 years ago

What two main gasses are exchanged during the process of breathing??

Zina [86]

Oxygen and carbon dioxide

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3 years ago

When are car velocity is positive and acceleration is negative, what is happening to the cars motion

DanielleElmas [232]

The motion of the car is negative

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3 years ago

Answer ?

morpeh [17]

Answer:

2.75 m/s^2

Explanation:

The airplane's acceleration on the runway was 2.75 m/s^2

We can find the acceleration by using the equation: a = (v-u)/t

where a is acceleration, v is final velocity, u is initial velocity, and t is time.

In this case, v is 71 m/s, u is 0 m/s, and t is 26.1 s Therefore: a = (71-0)/26.1

a = 2.75 m/s^2

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2 years ago

a) What is the average useful power output of a person who does6.00×10^6Jof useful work in 8.00 h? (b) Working at this rate, how

NARA [144]

Answer:

208.33 W

141.26626 seconds

Explanation:

E = Energy = $6\times 10^6\ J$

t = Time taken = 8 h

m = Mass = 2000 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Height of platform = 1.5 m

Power is obtained when we divide energy by time

$P=\frac{E}{t}\\\Rightarrow P=\frac{6\times 10^6}{8\times 60\times 60}\\\Rightarrow P=208.33\ W$

The average useful power output of the person is 208.33 W

The energy in the next part would be the potential energy

The time taken would be

$t=\frac{E}{P}\\\Rightarrow t=\frac{mgh}{208.33}\\\Rightarrow t=\frac{2000\times 9.81\times 1.5}{208.33}\\\Rightarrow t=141.26626\ s$

The time taken to lift the load is 141.26626 seconds

5 0

3 years ago