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Komok [63]
3 years ago
12

Imagine that person B is more massive than person A in the picture above.

Physics
1 answer:
Masja [62]3 years ago
6 0
Hippity hoppity your points are my property
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A business letter is informal correspondence and is sent to people within
jarptica [38.1K]

Answer:

FALSE!!!

Explanation:

Business letters are formal and normally given to someone of higher importance.

5 0
3 years ago
How do metal detcors operate
Masja [62]
Metal detectors work by transmitting an electromagnetic field from the search coil into the ground. Any metal objects (targets) within the electromagnetic field will become energised and retransmit an electromagnetic field of their own.
5 0
3 years ago
The change in the angle of circular motion is analogous to ____ in linear motion
snow_lady [41]

The change in the angle of circular motion is analogous to <u>linear velocity</u> in linear motion

<u>Explanation:</u>

We define angular velocity ω as the rate of change of an angle. The greater the rotation angle in a given amount of time, the greater the angular velocity. angular velocity refers to how fast an object rotates or revolves relative to another point, i.e. how fast the angular position or orientation of an object changes with time.

The units for angular velocity are radians per second (rad/s). Angular velocity ω is analogous to linear velocity v. Linear velocity is the measure of “the rate of change of displacement with respect to time when the object moves along a straight path.” It is a vector quantity.

7 0
3 years ago
A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor i
svet-max [94.6K]

Answer:

0.261\ \text{m}

Explanation:

\Delta f = Change in frequency = 2.1 Hz

f = Frequency of source of sound = 440 Hz

v_m= Maximum of the microphone

v = Speed of sound = 343 m/s

T = Time period = 2 s

We have the relation

\Delta f=2f\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f}\\\Rightarrow v_m=\dfrac{2.1\times 343}{2\times 440}\\\Rightarrow v_m=0.8185\ \text{m/s}

Amplitude is given by

A=\dfrac{v_m T}{2\pi}\\\Rightarrow A=\dfrac{0.8185\times 2}{2\pi}\\\Rightarrow A=0.261\ \text{m}

The amplitude of the simple harmonic motion is 0.261\ \text{m}.

4 0
3 years ago
A dog leaps horizontally off a 70 m cliff with a speed of 6 m/s, how far from the base will the dog land?
iris [78.8K]

Answer:

\Delta x=22.67786838m

Explanation:

Let's use projectile motion equations. First of all we need to find the travel time. So we are going to use the next equation:

y-y_0=v_o*sin(\theta)*t-\frac{1}{2}*t^2 (1)

Where:

y=Final\hspace{3}position\hspace{3}at\hspace{3}y-axis

y_o=Initial\hspace{3}position\hspace{3}at\hspace{3}y-axis

v_o=initial\hspace{3}velocity

t=travel\hspace{3}time

g=gravity\hspace{3}constant

\theta=Initial\hspace{3}launch\hspace{3}angle

In this case:

\theta=0

Because the dog jumps horizontally

Let's asume the gravity constant as:

g=9.8

y=0

Because when the dog reach the base the height is 0

y_o=70

v_o=6

Now let's replace the data in (1)

y_o-\frac{1}{2} *(9.8)*t^2+70

Isolating t:

t=\pm\sqrt{\frac{2*70}{9.8} } =3.77964473

Finally let's find the horizontal displacement using this equation:

\Delta x=v_o*cos(\theta)*t

Replacing the data:

\Delta x=6*1*3.77964473=22.67786838m

8 0
3 years ago
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