All categories

2 years ago

HELP MEEEE!!!!!

1 answer:

7 0

Just tell the child what he cannot do So that way he knows what to do and what not to do because physical punishment could probably get you in jail so that I would not do but I don't know what would happen if you physical punishment a child

You might be interested in

Do you think it would take more force to transport five blocks in the sled or in the wagon?

enot [183]

It will depend on the frictional force involved in the two. I think it will take more force in sled.

6 0

4 years ago

Read 2 more answers

Anna is sitting in a moving cart and throws a ball straight up. Theoretically, the ball should land in the cart, but it lands on

Likurg_2 [28]

Answer:

Reason for the difference in the ranges of the ball and the cart:

"the average speed of the cart is less than the instant speed of the cart at the time of throwing the ball".

Explanation:

Assuming that the air friction is negligible.

Given that the ball lands on the ground a little before the cart.

So, the range of the ball is more than the range of the cart in the same time interval.

Let the instant speed of the cart is v m/s at the time of throwing the ball in the vertically upward direction, so the speed of the ball in the horizontal direction = v m/s.

Let t be the total time of flight of the ball.

As the gravitational force is acting in the downward direction so it will not change the horizontal velocity of the ball.

So, the range covered by the ball $= vt$ m.

Let u be the average speed of the cart for the time t s (same as the time of flight of ball).

So, the distance by the cart $= ut$ m

As the range of the ball is more than the range of the cart in the same time interval, so

$vt > ut \\\\\Rightarrow v>u.$

So, the reason for the difference in the ranges of the ball and the cart is "the average speed of the cart is less than the instant speed of the cart at the time of throwing the ball".

5 0

3 years ago

How many known planets are in our galaxy?

strojnjashka [21]

There are 100 billion planets

8 0

3 years ago

A diver runs horizontally off the end of a 3.0-m-high diving board with an initial speed of 1.8 m/s.Given that the diver's initi

liberstina [14]

Thank you for posting your question your question here. Below is the solution:
time = 3.00 / 1.75

time = 1.714 

now 

distance = (initial velocity + final velocity) / 2 * time/ 1 

Hence

3 = ( 1.75 + final velocity) / 2 * 1.714 

3.5 - 1.75 = final velocity 

Therefore, the final velocity is 1.75 m /s

5 0

3 years ago

Read 2 more answers

The electron density in copper is 8.49 × 1028 electrons/m3. When a 1.00 A current is present in a copper wire with a 0.40 cm2 cr

vichka [17]

Answer:

Drift velocity in m/s is $1.84 \times 10^{-8}\ m/s$ .

Explanation:

Formula for Drift Velocity is:

$u = \dfrac{I}{nAq}$

Where I is the current

n is the number of electrons in 1 $m^3$ or the electron density

A is the area of cross section and

q is the charge of one electron.

We are given the following:

n = $8.49 \times 10^{28}\ electrons/m^3$

I = 1 A

A = 0.40 $cm^2$ = 40 $\times 10^{-4}$ $m^{2}$

We know that q = $1.6\times10^{-19} C$

Putting all the values to find drift velocity:

$u = \dfrac{1}{8.49 \times 10 ^{28} \times 40 \times 10^{-4}\times 1.6 \times 10^{-19}}\\u = \dfrac{1}{543.36 \times 10 ^{5} }\\u = 1.84 \times 10^{-8}\ m/s$

So, drift velocity in m/s is $1.84 \times 10^{-8}\ m/s$ .

3 0

3 years ago