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Katarina [22]
3 years ago
9

What is the distance between -6,2 and 2,6​

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

Answer:

4 √ 5

Step-by-step explanation: use the distance formula

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What is the probabibility of rolling a sum of 10 when rolling two number cubes?
Alja [10]

Answer: 1 over 12

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
The population of California is approximately 38,040,000. The population of Texas is about 2.606 × 107. What is the approximate
liubo4ka [24]

Answer:

The total population of these two states is:

3.804\times \:\:10^7+2.606\times \:\:10^7\:=10^7\times \:\:6.41

Therefore, option C is correct.

Step-by-step explanation:

  • The population of California is approximately 38,040,000.
  • The population of Texas is about 2.606 × 10⁷.

Writing the population of California i.e.38,040,000  in scientific notation by moving the decimal point 7 places to the left and dropping the 0's on the right  side as they're after the decimal point now.

i.e.

38,040,000 = 3.804 x 10⁷

So adding 3.804 x 10⁷ and 2.606 × 10⁷

i.e.

3.804\times \:10^7+2.606\times \:10^7

\mathrm{Add\:similar\:elements:}\:10^7\times \:3.804+10^7\times \:2.606=10^7\times \:6.41

Thus, the total population of these two states is:

3.804\times \:\:10^7+2.606\times \:\:10^7\:=10^7\times \:\:6.41

Therefore, option C is correct.

4 0
4 years ago
Use the numbers 0 through 9 to complete each equation so the statement about it's solution is true
belka [17]
For the first equation, to get an equation that only has 1 solution your two missing numbers could be 3x and 6. This is because when you solve it, you get 7x + 2 = 3x + 6
- 3x
4x + 2 = 6
- 2
4x = 4
x = 1

For the second equation, your two numbers could be 7x and 4, because it means that x has to be different as 7 multiplied by one number and added to 2 cannot equal 7 multiplied by the same number but added to 4.

I hope this helps!
3 0
3 years ago
.....?????...........
Liula [17]

You need 3a^3 to equal a^3, so you would need at subtract 2a^3.

Since the problem is addition, add - 2a^3:

3a^3 + -2a^3 = 3a^3 - 2a^3 = a^3

Then you have -5b^3 and you need it to equal b^^3, so you would need to add 6b^3:

-5b^3 + 6b^3 = b^3

First box would be -2

Second box would be 6

3 0
3 years ago
Is the HCF of a^3-8, a^4+16 and a^3+2a^2+4a just 1?<br> Please answer........
Flauer [41]
First we find the factors
a^3-8 is the differnce between 2 perfect cubes and is factored out to
(a-2)(a^2+2a+4)
the factors are (a-2) and (a^2+2a+4)

a^4+16
this is not factorable, unless you mistiped it and it was really a^4-16
the factor is 1


a^3+2a^2+4a
factor out the a
a(a^2+2a+4)
this is the most factored out form
the factors are (a) and (a^2+2a+4)


there are no common factors except 1 so 1 is the answer
3 0
3 years ago
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