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4 years ago

To what part of a plant does the stem sliver water and nutrients

Chemistry

2 answers:

Vladimir79 [104]4 years ago

5 0

<span>Stems carry water and nutrients taken up by the roots to the leaves.</span>

ikadub [295]4 years ago

5 0

From the roots, the stem carries up the water and nutrients for the plant

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What is the difference between a living thing and a nonliving thing? In Animal Cells

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The term living thing refers to things that are now or once were alive, a nonliving thing is anything that was never alive.

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4 years ago

What are the reasons to determine the melting point of a sample in a melting point apparatus?.

IRINA_888 [86]

Answer:

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3 years ago

X-ray photons with a wavelength of 0.135 nm . express the energy numerically in kilojoules per mole.

STALIN [3.7K]

Using E=hν where h is Planck's constant and v is the frequency of the photon. In the question above,the wavelenght is given so we can find the frequency of the photon using c=λν. c is a constant =3*10^8 so frequency is equal to
(3*10^8)/0.135*10^-9. Then use ur frequency in the eqn above using h 6.626*10^-34

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3 years ago

Read 2 more answers

The map shows the global distribution of amphibians. The number of different amphibian species found in an area is

harkovskaia [24]

What's up? im not gonna type a whole thing but you probably could make do with this info:

amphibians need water and a moist environment. north africa will constantly have droughts/low amounts of water, so amphibians could not survive there. in Antarctica, it is much too cold and as cold blooded animals they would simply freeze to death

best of luck with your studies

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2 years ago

Burka [1]

Answer:

$\large \boxed{\text{E) 721 K; B) 86.7 g}}$

Explanation:

Question 7.

We can use the Combined Gas Laws to solve this question.

a) Data

p₁ = 1.88 atm; p₂ = 2.50 atm

V₁ = 285 mL; V₂ = 435 mL

T₁ = 355 K; T₂ = ?

b) Calculation

$\begin{array}{rcl}\dfrac{p_{1}V_{1}}{T_{1}}& =&\dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{1.88\times285}{355} &= &\dfrac{2.50\times 435}{T_{2}}\\\\1.509& = &\dfrac{1088}{T_{2}}\\\\1.509T_{2} & = & 1088\\T_{2} & = & \dfrac{1088}{1.509}\\\\ & = & \textbf{721K}\\\end{array}\\\text{The gas must be heated to $\large \boxed{\textbf{721 K}}$}$

Question 8. I

We can use the Ideal Gas Law to solve this question.

pV = nRT

n = m/M

pV = (m/M)RT = mRT/M

a) Data:

p = 4.58 atm

V = 13.0 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 385 K

M = 46.01 g/mol

(b) Calculation

$\begin{array}{rcl}pV & = & \dfrac{mRT}{M}\\\\4.58 \times 13.0 & = & \dfrac{m\times 0.08206\times 385}{46.01}\\\\59.54 & = & 0.6867m\\m & = & \dfrac{59.54}{0.6867 }\\\\ & = & \textbf{86.7 g}\\\end{array}\\\text{The mass of NO$_{2}$ is $\large \boxed{\textbf{86.7 g}}$}$

7 0

3 years ago