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stira [4]
2 years ago
9

The map shows the global distribution of amphibians. The number of different amphibian species found in an area is

Chemistry
1 answer:
harkovskaia [24]2 years ago
8 0
What's up? im not gonna type a whole thing but you probably could make do with this info:

amphibians need water and a moist environment. north africa will constantly have droughts/low amounts of water, so amphibians could not survive there. in Antarctica, it is much too cold and as cold blooded animals they would simply freeze to death

best of luck with your studies
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An ideal gas in a cylindrical container of radius r and height h is kept at constant pressure p. The bottom of the container is
Juli2301 [7.4K]

Answer:

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}  

Explanation:

The gas ideal law is  

PV= nRT (equation 1)

Where:

P = pressure  

R = gas constant  

T = temperature  

n= moles of substance  

V = volume  

Working with equation 1 we can get  

n =\frac{PV}{RT}

The number of moles is mass (m) / molecular weight (mw). Replacing this value in the equation we get.

\frac{m}{mw} =\frac{PV}{RT}  or  

m =\frac{P*V*mw}{R*T}   (equation 2)

The cylindrical container has a constant pressure p  

The volume is the volume of a cylinder this is

V =(pi)*r^{2}*h

Where:

r = radius  

h = height  

(pi) = number pi (3.1415)

This cylinder has a radius, r and height, h so the volume is  V =(pi)*r^{2}*h

Since the temperatures has linear distribution, we can say that the temperature in the cylinder is the average between the temperature in the top and in the bottom of the cylinder. This is:  

T =\frac{T_{1} + T_{O}}{2}  

Replacing these values in the equation 2 we get:

m =\frac{P*V*mw}{R*T}   (equation 2)

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}    

8 0
3 years ago
How many oxygen atoms are present in a formula unit of calcium acetate?
julsineya [31]

So we end up with a total of four oxygen atoms for this calcium acetate unit and guys that truly it for this one.

6 0
3 years ago
An object was measured by a worker as
Alexeev081 [22]

Answer:.633

Explanation:

I have know idea but it was right

3 0
3 years ago
How many grams of oxygen are required too burn 8.8g of c3h8?
hichkok12 [17]
From the balanced equation: 
<span>1mol C3H8 requires 5mol O2 for combustion </span>
<span>Molar mass C3H8 = 44g/mol </span>
<span>8.8g C3H8 = 8.8/44 = 0.2mol C3H8 </span>
<span>This will require 5*0.2 = 1.0mol O2 </span>
<span>Molar mass O2 = 32g/mol </span>
<span>Therefore 32g of O2 required.


</span>
4 0
3 years ago
Ions that have the same electron configuration are called
Katena32 [7]
Such ions are said to be isoelectronic
3 0
3 years ago
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