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stira [4]
2 years ago
9

The map shows the global distribution of amphibians. The number of different amphibian species found in an area is

Chemistry
1 answer:
harkovskaia [24]2 years ago
8 0
What's up? im not gonna type a whole thing but you probably could make do with this info:

amphibians need water and a moist environment. north africa will constantly have droughts/low amounts of water, so amphibians could not survive there. in Antarctica, it is much too cold and as cold blooded animals they would simply freeze to death

best of luck with your studies
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Hypothesis and Data Collection Part A The image shows three different liquids: water, water with salt, and vinegar. The pH of ea
Norma-Jean [14]

Answer:

The water would be neutral, (usually 7). The salt water would be the same (7) and the vinegar would be very acidic. (probably 2).

Explanation:

7 0
2 years ago
g Write a molecular equation for the precipitation reaction that occurs (if any) when the following solutions are mixed. If no r
Mrac [35]

Answer:

CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓

Explanation:

We identify the reactants:

CuBr₂ and Pb(CH₃COO)₂

The products will be: Cu(CH₃COO)₂ and PbBr₂

You may know these information:

Salts from acetate are soluble.

Bromide can make solid salts with these cations: Ag⁺, Pb²⁺, Hg₂²⁺, Cu⁺

PbBr₂ is formed, so this will be our precipitate

The equation is:

CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓

8 0
2 years ago
What is the difference between cell and cellmembrane​
lisov135 [29]

Answer:

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I hope this helps!

3 0
3 years ago
Which carbon compound is soft, slippery, a decent electricity conductor, and bonded in a way that forms planes?
Mashcka [7]
Your answer is Graphite
8 0
3 years ago
Read 2 more answers
What is the enthalpy of combustion (per mole) of C4H10 (g)? 
Artemon [7]
The balanced chemical reaction for the complete combustion of C4H10 is shown below:

                    C4H10 + (3/2)O2 --> 4CO2 + 5H2O

The enthalpy of formation are listed below:
          C4H10: -2876.9 kJ/mol
              O2:   none (because it is pure substance)
             CO2: -393.5 kJ/mol
             H2O: -285.8 kJ/mol

The enthalpy of combustion is computed by subtracting the total enthalpy formation of the reactants from that of the products.

               ΔHc = (4)(-393.5 kJ/mol) + (5)(-285.8 kJ/mol) - (-2876.9 kJ/mol)
                       = -<em>126.1 kJ</em>

Thus, the enthalpy of combustion of the carbon is -126.1 kJ. 
5 0
3 years ago
Read 2 more answers
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