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2 years ago

Write an inequality that represents the graph.

Mathematics

1 answer:

Anika [276]2 years ago

5 0

Answer:

$y - 2x - 1 = 0$

Step-by-step explanation:

the slope is :

$\tan( \alpha ) = 4 \div 2 = 2$

at a pt on graph , when

$x = 1 \\ y = 3 \\$

therefore, coordinates are (1,3)

The equation is :

$(y - 3) = slope \times (x - 1) \\ (y - 3) = 2 \times (x - 1) \\ y - 3 = 2x - 2 \\ y - 2x - 1 = 0$

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F(5) is 3, because the graph hits 3 when the x is 5.

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2 years ago

The table shows the distances and times that four rowboats traveled. Which rowboat was the fastest?

g100num [7]

Answer: the answer is C

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3 years ago

Write the algebraic expression of “the sum of a multiple of 3 and the number one greater than multiple of 3”

marysya [2.9K]

Answer:

9 IS THE ANSWER

Step-by-step explanation:

3*3=9

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2 years ago

It is given 5 and h + 1 are the roots of the quadratic equation x² + (k - 1)x - 5 = 0,where h and k are constant.Find the value

Liono4ka [1.6K]

Answer:

Hello,

Step-by-step explanation:

$5\ is\ a \ root \of \ x^2+(k-1)*x-5=0\\\\5^2+(k-1)*5-5=0\\\\5*(k-1)+20=0\\\\k-1=\dfrac{-20}{5} \\\\k=-4+1\\\\\boxed{k=-3}\\$

h+1 is thus a root of x²+(-3-1)*x-5=0

x²-4x-5=0

x²+x-5x-5=0

x(x+1)-5(x+1)=0

(x+1)(x-5)=0

h+1=-1

6 0

3 years ago

Given that P = (-7, 16) and Q = (-8, 7), find the component form and magnitude of vector QP .

Katyanochek1 [597]

Answer:

a)The component form is

$\vec {QP}=\binom{ - 1}{ - 8}$

b)The magnitude is √65

c) <2,14>

Step-by-step explanation:

Recall that:

$\vec {QP}=\vec {OP}-\vec{OQ}$

We substitute the position vectors to get:

$\vec {QP}=\binom{ - 8}{7} - \binom { - 7}{15}$

We subtract the corresponding components to obtain:

$\vec {QP}=\binom{ - 8 - - 7}{7 - 15}$

This gives:

$\vec {QP}=\binom{ - 8 + 7}{7 - 15}$

This simplifies to:

$\vec {QP}=\binom{ - 1}{ - 8}$

The magnitude of a vector in the component form:

$\binom{x}{y}$

$\sqrt{ {x}^{2} + {y}^{2} }$

This means:

$|\vec {QP}|= \sqrt{ {( - 1)}^{2} + {( - 8)}^{2} }$

This simplifies to:

$|\vec {QP}| = \sqrt{ 1 + 64 }$

$|\vec {QP}| = \sqrt{ 65 }$

c) We have the vectors u = <4, 8>, v = <-2, 6>.

We want to find:

u+v

This implies that:

u+v=<4,8>+<-2,6>

We add the corresponding components to get;

u+v=<4+-2,8+6>

This simplifies to:

u+v=<2,14>

7 0

3 years ago