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3 years ago

Dirical Formulas

Chemistry

1 answer:

Anvisha [2.4K]3 years ago

7 0

C₂HO₂Br₃

Explanation:

Given parameters:

Carbon = 8.09%

Hydrogen = 0.34%

Oxygen = 10.78%

Bromine = 80.78%

Unknown:

Empirical formula = ?

Solution:

The empirical formula is the simplest formula of a compound.

To find it, we use the process below:

C H O Br

Percent

compo-

sition 8.09 0.34 10.78 80.78

Molar

mass 12 1 16 80

Numb-

of moles 8.09/12 0.34/1 10.78/16 80.78/80

0.68 0.34 0.68 1

Divide

smallest 0.68/0.34 0.34/0.34 0.68/0.34 1/0.34

2 1 2 3

Empirical formula C₂HO₂Br₃

learn more:

Empirical formula brainly.com/question/2790794

#learnwithBrainly

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You have 200 g of a substance with a molar mass of 150 g/mol. How many moles of the substance do you have? 0.75 mol 1.00 mol 1.3

tigry1 [53]

Answer:

Explanation:

200 g/150 g/mol = 1.33 mol

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3 years ago

The following questions are about ethyl bromide,n-propyl bromide, isopropyl bromide,t-butyl bromide, & neopentyl bromide

mrs_skeptik [129]

Answer:

a) Watch the attaccment

b) Ethyl bromide is more reactive than n-propyl bromid, and this more than neopentyl bromide. Ethyl bromide has less steric hindrance than the others, to SN2 reactions.

c) t-butyl bromide is more reactive than isopropyl bromide, and this more than ethyl bromide. t-butyl bromide structure stabilize the carbocation, better than the others.

Explanation:

Speed of SN2 reactions depends on steric hindrance, the less hindrance, the most reaction speed, meaning more reactivity. Then, those linear structures are more reactive to SN2 reactions.

In the other hand, speed of SN1 reactions depends on the stability of the carbocation formed. Structure with ramifications can stabilize better the carbocation, these structures are more reactive to SN1 reactions.

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7 0

3 years ago

a. If 42.5 g of CH3OH reacts with 22.8 L of O2 at 27°C and a pressure of 2.00 atm, calculate the number of grams of water vapor

Korvikt [17]

Answer:

The mass of water vapor is 44.46 grams

The volume of water is 30.37 L

Explanation:

Step 1: Data given

Mass of CH3OH =42.5 grams

Molar mass CH3OH = 32.04 g/mol

Volume of O2 = 22.8 L

Pressure = 2.00 atm

Step 2: The balanced equation

2CH3OH + 3O2 → 2CO2 + 4H2O

Step 3: Calculate moles CH3OH

Moles CH3OH = mass CH3OH / molar mass CH3OH

Moles CH3OH = 42.5 grams / 32.04 g/mol

Moles CH3OH = 1.326 moles

Step 4: Calculate moles O2

p*V = n*R*T

⇒with p = the pressure = 2.00 atm

⇒with V = the volume of O2 = 22.8 L

⇒with n = the moles of O2 = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*Atm/mol*K

⇒with T = the temperature = 27 °C = 300 K

n = (p*V) / (R*T)

n = (2.00 * 22.8) / (0.08206*300)

n = 1.85 moles

Step 5: Calculate the limiting reactant

For 2 moles CH3OH we need 3 moles O2 to produce 2 moles CO2 and 4 H2O

O2 is the limiting reactant. It will completely be consumed ( 1.85 moles). CH3OH is in excess. There will react 2/3*1.85 = 1.233 moles. There will remain 1.326 - 1.233 = 0.093 moles

Step 6: Calculate moles products

For 2 moles CH3OH we need 3 moles O2 to produce 2 moles CO2 and 4 H2O

For 1.85 moles O2 we'll have 1.233 moles CO2 and 2.467 moles H2O

Step 7: Calculate mass H2O

Mass H2O = moles H2O * molar mass H2O

Mass H2O = 2.467 moles * 18.02 g/mol

Mass H2O = 44.46 grams

Step 8: Calculate volume H2O

p*V = n*R*T

⇒with p = the pressure = 2.00 atm

⇒with V = the volume of H2O = TO BE DETERMINED

⇒with n = the moles of H2O = 2.467 moles

⇒with R = the gas constant = 0.08206 L*Atm/mol*K

⇒with T = the temperature = 27 °C = 300 K

V = (n*R*T)/p

V = (2.467 * 0.08206 * 300) / 2.00

V = 30.37 L

The mass of water vapor is 44.46 grams

The volume of water is 30.37 L

3 0

3 years ago

The process of ____ occurs when magma, lava, or a solute in a solution becomes a solid and the internal components will arrange

satela [25.4K]

Answer:

D. Crystallization

Explanation:

Let's clarify the irrelevant terms first.

unification: This term has nothing to do with chemistry at all
lithification: When the problem mentions magma and lava, you might think that this term is related to the process here. However, 'lithification' do have a precise meaning in geology. It refers to the process where sediments collapses into one single rock under pressure, which has nothing to do with the process mentioned here.

Now, for 2 terms that might confuse you: 'solidification' and 'crystallization' these also has precise scientific definition

Solidification is defined the process where substances in liquid phase changes its phase to solid. On first glance, this answer might seems correct, and yes, it is correct for this question. But not the most correct.

The keyword here is

'the internal components will arrange its self in an organized pattern.'

Crystallization is a special case of Solidification where the atoms or molecules of liquid solidify by spontaneously arrange themselves in periodic, ordered, and organized pattern. It might or might not happen during solidification depending on cooling rate, viscosity of liquid, and other factors.

So, Crystallization is the most correct answer here.

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3 years ago

how is substitution reaction in alkanes different from dehydrogenation reaction since both involve removing a hydrogen atom from

Ilia_Sergeevich [38]

Answer:

See Explanation

Explanation:

A substitution reaction means the replacement of one or more hydrogen atoms in an alkane by another atom or group. It does not introduce a double bond into the product. The product retains single bonds between the species present.

For instance;

CH4 + Cl2 -------> CH3Cl +HCl

is a substitution reaction

Dehydrogenation is the process of removing two hydrogen atoms from a saturated compound compound thereby yielding an unsaturated product.

E.g

C2H6 --------->C2H4 + H2

The key difference is that substitution reaction yields a saturated product while dehydrogenation yields an unsaturated product.

8 0

3 years ago