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3 years ago

_______ are prophylactic agents used to treat bronchoconstriction.

Chemistry

1 answer:

Brut [27]3 years ago

6 0

Bronchodilators <span>are prophylactic agents used to treat bronchoconstriction.</span>

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Use the following equation to answer question 1-4. Make sure you balance first.

worty [1.4K]

<h3>Answer:</h3>

5.2 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 6HCl + Fe₂O₃ → 2FeCl₃ + 3H₂O

[Given] 10.4 mol HCl

<u>Step 2: Identify Conversions</u>

[RxN] 6 mol HCl = 3 mol H₂O

<u>Step 3: Stoichiometry</u>

Set up: $\displaystyle 10.4 \ mol \ HCl(\frac{3 \ mol \ H_2O}{6 \ mol \ HCl})$
Multiply/Divide: $\displaystyle 5.2 \ mol \ H_2O$

4 0

3 years ago

What types of energy can be moved through conductors

Luden [163]

<span>The two types of energy that can be moved through conductors are electrical energy and thermal energy. Conductors are materials that allow electrons to flow freely or transfers heat more easily than other substances. Heat is transfered in conductors when fast moving particles (contains more heat) crash into slow moving particles. conductors allow electrons to flow freely from one object to another in contact. Metals are usually excelent conductors of heat and electricity. </span>

8 0

3 years ago

Help. If an element has a charge of 4+, how many more protons does it have than electrons?

Andreyy89

Charge = Number of Protons - Number of Electrons = 4

So, Your Answer would be: 4

Hope this helps!

8 0

3 years ago

Calculate the fraction of lattice sites that are schottky defects for cesium chloride at its melting temperature (645oc). assume

baherus [9]

Answer : 7.87 X $10^{-6}$ .

Explanation : To find the fraction of schottky defects in the given lattice of CsCl,

we use the formula, $\frac{N_{s} }{N}} = exp ( \frac{-Q_{s}}{2KT} )$

on solving with the given values , $Q_{s}= 1.86 eV$ and T as 645 + 273 K and rest are the constants.

$\frac{N_{s} }{N}} = exp ( \frac{-1.86 eV}{2 X (8.62 X 10^{-5}) X (645 +273)} )$

we get the answer as 7.87 X $10^{-6}$ .

6 0

3 years ago

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Based on the Hertzprung-Russell diagram, which statement is true? OA. Main sequence stars with low temperatures tend to have low

ololo11 [35]

Main sequence stars with low temperatures tend to have low luminosity is based on Hertzprung-Russell diagram

<h3>What is the Hertzsprung-Russell diagram's main sequence?</h3>

The bright, hot stars in the image's upper left are the main sequence group, which stretches roughly diagonally to the lower right (dim and cool). In the bottom left are white dwarfs, which are small, faint, and hot. In the top right are giant and supergiant stars, which are big, bright, and cool.

<h3>What is the main sequence star H-R diagram trend?</h3>

Main sequence stars have a wide range of effective temperatures, but because they are brighter at higher temperatures, they normally follow a band from the bottom right to the top left of the diagram. Inside the cores, hydrogen and helium are fusing together.

To know more about H-R diagram visit:

brainly.com/question/13635125

#SPJ9

6 0

2 years ago

Read 2 more answers