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hram777 [196]
3 years ago
8

_______ are prophylactic agents used to treat bronchoconstriction.

Chemistry
1 answer:
Brut [27]3 years ago
6 0
Bronchodilators <span>are prophylactic agents used to treat bronchoconstriction.</span>
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How many moles of aluminum do 4.40×1024 aluminum atoms represent?
zhannawk [14.2K]
For this problem we use the Avogadro's number which is an empirical value that relates the number of particles to the number of moles. Its approximated value is 6.022×10²³ atoms/mole. The solution is as follows:

4.40×10²⁴ aluminum atoms * 1 moles/6.022×10²³ atoms = 7.306

Thus, there are 7.306 moles of aluminum.
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4 years ago
Which of the following best defines molar mass?
coldgirl [10]

Answer:

D. the mass of one mole of a substance

Explanation:

The molar mass of a substance is the mass in grams of one mole of the substance.

  • For an element, the molar mass is the relative atoms mass expressed in grams.
  • For example 23g of Na, 40g of oxygen
  • For compounds, molar mass is the gram -formula or gram - molecular weight.
  • This is determined by the addition of its component atomic masses and then expressed in grams.
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Oro estructura de lewis
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Answer:

La configuración de estado fundamental del oro es [Xe]5d106s1 La diferencia de nivel de energía entre el 6s y el 5d es pequeña. Esto hace posible que uno de los dos electrones 6s esté en los orbitales 5d.

Explanation:

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3 years ago
How are gold medal cells and human cells alike and different
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Your skin is a tougher substance

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What is the frequency and energy per quantum (in Joules) of :
viktelen [127]

(a) f = 5.00 × 10²⁰ Hz, E = 3.32 × 10⁻¹³ J;

(b) f = 1.20 × 10¹⁰ Hz, E = 7.96 × 10⁻²⁴J.

<h3>Explanation</h3>

What's the similarity between a gamma ray and a microwave?

Both gamma rays and microwave rays are electromagnetic radiations. Both travel at the speed of light at 3.00 \times 10^{8}\;\text{m}\cdot\text{s}^{-1} in vacuum.

f = \dfrac{c}{\lambda}

where

  • f is the frequency of the electromagnetic radiation,
  • c is the speed of light, and
  • \lambda is the wavelength of the radiation.

(a)

Convert all units to standard ones.

\lambda = 0.600\;\text{pm} = 0.600 \times 10^{-12} \;\text{m}.

The unit of f shall also be standard.

f = \dfrac{c}{\lambda} = \dfrac{3.00\times 10^{8}\;\text{m}\cdot\text{s}^{-1}}{0.600\times 10^{12}\;\text{m}} = 5.00 \times 10^{20}\;\text{s}^{-1}= 5.00\times 10^{20}\;\text{Hz}.

For each particle,

E = h\cdot f,

where

  • E is the energy of the particle,
  • h is the planck's constant where h = 6.63\times 10^{-34}\;\text{J}\cdot\text{s}^{-1}, and
  • f is the frequency of the particle.

E = h \cdot f = 6.63\times10^{-34}\;\text{J}\cdot\text{s}\times 5.00\times 10^{20}\;\text{s}^{-1} = 3.32\times10^{-13}\;\text{J}.

(b)

Try the steps in (a) for this beam of microwave with

  • \lambda = 2.50 \;\text{cm} = 2.50\times 10^{-2}\;\text{m}.

Expect the following results:

  • f = 1.20\times 10^{10}\;\text{Hz}, and
  • E = 7.96\times 10^{-24}\;\text{J}.
4 0
3 years ago
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