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nata0808 [166]
3 years ago
15

two vertical poles stand side by side. one post is 8ft tall while the other is 17ft tall. if a 24ft wire is stretched between th

e tops of the post, how far apart are the posts?
Mathematics
1 answer:
Anna35 [415]3 years ago
6 0

Answer:

It's a right triangle.

Step-by-step explanation:

The hypotenuse is 24 feet

The vertical side is 17 - 8 = 9 feet.

The distance is the 3rd side.

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What are the answers
dlinn [17]

Answer:

See below

Step-by-step explanation:

The ratio of the secants is the same when set up as full length to external length.

Formula

MN/LN = QN/PN

Givens

LN = 22 + 14 = 36

MN = 14

PN = 32

QN = x

Solution

14/36 = x / (32)  Multiply both sides by 32

14*32 / 36 = x    Combine 14 and 32

448/36 = x         Divide by 36 and switch

x = 12.4

Answers

PN (External) = 13 is the closest answer

Length LN = 36

6 0
3 years ago
Two variables are correlated with r = 0.44.
butalik [34]
It's moderate positive because when the number is closer to zero the weaker it is and the closer to one its stronger so since 0.44 is in more in the middle it moderate and since there is no negative sign which is - then it moderate positive. Btw I took the test and it was right. 
3 0
3 years ago
A praying mantis is an interesting insect that can rotate its head 180 degrees.Suppose the praying mantis at the right is 10.5 c
Charra [1.4K]
10.5 = 10 1/2 explanation is 1÷2 =0.5
3 0
3 years ago
Read 2 more answers
A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular custome
Ludmilka [50]

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

Seats available = 17 - 14 = 3

Remaining reservations, n = 19 - 14 = 5

P (A remaining passenger will arrive), <em>p</em> = 0.52

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.52.

(1)

Compute the probability of overbooking  as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

                                        =P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

=P(X

Thus, the probability that the flight has empty seats is 0.4625.

4 0
3 years ago
Z = 18ba - 6b<br><br> Solve for a
adelina 88 [10]

Answer:

   

Step-by-step explanation:

       

7 0
2 years ago
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