Electric charge? Hope that kinda gives you an idea... I am not sure if that is the answer or not though.
Answer:
Tuesday bc instead of running he/she was walking bc he/she might not have as much energy
Explanation:
Answer:
The stored energy is
.
Explanation:
Given that,
One side of square plates = 8.5 cm
Distance = 2.5 mm
Charge = 14 nC
We need to calculate the energy stored
The energy is stored by the electric field between two square plates is defined as,
![U=\dfrac{1}{2}\times\epsilon_{0}\times(\dfrac{q}{A\epsilon_{0}})^2\times A\times D](https://tex.z-dn.net/?f=U%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%5Cepsilon_%7B0%7D%5Ctimes%28%5Cdfrac%7Bq%7D%7BA%5Cepsilon_%7B0%7D%7D%29%5E2%5Ctimes%20A%5Ctimes%20D)
![U=\dfrac{1}{2}\times\dfrac{q^2}{A\epsilon_{0}}\times D](https://tex.z-dn.net/?f=U%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%5Cdfrac%7Bq%5E2%7D%7BA%5Cepsilon_%7B0%7D%7D%5Ctimes%20D)
We calculate the area iof square plates
![A=(8.5\times10^{-2})^2](https://tex.z-dn.net/?f=A%3D%288.5%5Ctimes10%5E%7B-2%7D%29%5E2)
![A=0.007225=72.2\times10^{-4}\ m^2](https://tex.z-dn.net/?f=A%3D0.007225%3D72.2%5Ctimes10%5E%7B-4%7D%5C%20m%5E2)
Now, put the value into the formula
![U=\dfrac{1}{2}\times\dfrac{(14\times10^{-9})^2}{72.2\times10^{-4}\times8.85\times10^{-12}}\times2.5\times10^{-3}](https://tex.z-dn.net/?f=U%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%5Cdfrac%7B%2814%5Ctimes10%5E%7B-9%7D%29%5E2%7D%7B72.2%5Ctimes10%5E%7B-4%7D%5Ctimes8.85%5Ctimes10%5E%7B-12%7D%7D%5Ctimes2.5%5Ctimes10%5E%7B-3%7D)
![U=3.83\times10^{-6}\ J](https://tex.z-dn.net/?f=U%3D3.83%5Ctimes10%5E%7B-6%7D%5C%20J)
Hence, The stored energy is
.
Ultraviolet radiation from the sun is controlled by the ozone but if it infiltrates into the atmosphere it becomes a hazard. The uv reaches our eyes and darkens the retina and blurs vision. The fovea becomes insensitive and the cells dormant. This causes gradual blindness.
C. a cello playing music at the concert