Answer:
The magnitude of the centripetal force to make the turn is 3,840 N.
Explanation:
Given;
radius of the cured road, r = 400 m
speed of the car, v = 32 m/s
mass of the car, m = 1500 kg
The magnitude of the centripetal force to make the turn is given as;

where;
Fc is the centripetal force

Therefore, the magnitude of the centripetal force to make the turn is 3,840 N.
Answer:
8 time increase in K.E.
Explanation:
Consider Mass of truck = m kg and speed = v m/s then
K.E. = 1/2 ×mv²
If mass and speed both are doubled i.e let m₀ = 2m and v₀ = 2v then
(K.E.)₀ = 1/2 ×2m(2v)²
(K.E.)₀ = 8 (1/2 × mv²) = 8 × K.E.
Answer: 0.56 m/s
Explanation:
Hi, to answer this question we have to apply the formula of the conservation of momentum.
m1 v1 = m2 v2 (because the system is stationary at the beginning)
Where:
m1 = mass of the astronaut
v1= velocity of the astronaut
m2= mass of the satellite
v2= velocity of the satellite
Replacing with the values given and solving:
86 kg (2.35m/s) = 360 kg v2
202.1 kgm/s=360kg v2
202.1kgm/s /360kg =v2
v2 = 0.56 m/s
Feel free to ask for more if needed or if you did not understand something.