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bogdanovich [222]
3 years ago
8

Describe metallurgy. Check all that apply.

Physics
1 answer:
mylen [45]3 years ago
7 0

Answer:

A, C, D

Explanation:

got it right

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What is dark energy and what evidence do astronomers have that it is an important component of the universe?
PSYCHO15rus [73]

Answer:

The existance of dark energy was suggested to help explain measurements, using Type Ia supernovae as distance indicators, that the expansion of the universe is speeding up and its acceleration requires a source of energy. Scientists suggested that It may be a new form of energy for which there is not yet a theoretical explanation. quantum mechanics predict that it may be the vacuum energy associated with "empty" space itself.

8 0
3 years ago
In the combo circuit diagrammed, R1 = 19.2 Ω, R2 = 20.7 Ω, and R3 = 25.8 Ω. Find the equivalent resistance of the circuit.
garik1379 [7]

Answer:

Equivalent resistance: 13.589 Ω

Explanation:

R series = R1 + R2 + R3 ...

\frac{1}{R_{eq} } = \frac{1}{R1} +\frac{1}{R2} +\frac{1}{R3} ...

Find the equivalent resistance of the right branch of the circuit:

R_{eq}  = R_{2} +R_{3} \\R_{eq} = 20.7 + 25.8 = 46.5 ohms

\frac{1}{R_{eq} } = \frac{1}{19.2} +\frac{1}{46.5}\\\\\frac{1}{R_{eq} } = 0.0735887097\\\\R_{eq} = 13.5890411

6 0
2 years ago
Dense water near the poles sinks, creating a current towards the equator. What would you expect to happen to this current if tem
Rudik [331]
It's not c or d :/!!!!!
3 0
3 years ago
Which of these is the movement of material cause by the interaction between worm and cool material?
mr Goodwill [35]
Convection Current  
This happens when there is a noteworthy contrast in temperature between two sections of a liquid. At the point when this temperature distinction exists, hot liquids rise and cool liquids sink, and after that streams, or developments, are made in the liquid
7 0
3 years ago
The drawing shows a skateboarder moving at 4.8 m/s along a horizontal section of a track that is slanted upward by 48° above the
Anna11 [10]
Let M = mass of the skier, 
v2 = his speed at the end of the track. 
By conservation of energy, 
1/2 Mv^2 = 1/2 Mv2^2 + Mgh 
Dividing by M, 
1/2 v^2 = 1/2 v2^2 + gh
 Multiplying by 2, 
v^2 = v2^2 + 2gh 
Or v2^2 = v^2 - 2gh 
Or v2^2 = 4.8^2 - 2 * 9.8 * 0.46 
Or v2^2 = 23.04 - 9.016 
Or v2^2 = 14.024 m^2/s^2-----------------------------(1) 
In projectile motion, launch speed = v2 
and launch angle theta = 48 deg 
Maximum height 
H = v2^2 sin^2(theta)/(2g) 
Substituting theta = 48 deg and value of v2^2 from (1),
 H = 14.024 * sin^2(48 deg)/(2 * 9.8) 
Or H = 14.024 * 0.7431^2/19.6 
Or H = 14.024 * 0.5523/19.6 
Or H = 0.395 m = 0.4 m after rounding off 
Ans: 0.4 m

The answer in this question is 0.4 m
4 0
3 years ago
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