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s2008m [1.1K]
4 years ago
12

Fill in the blanks!

Chemistry
2 answers:
erma4kov [3.2K]4 years ago
7 0
The freezing point of a solution will increase and the vapor pressure will increase with decreasing <span>molality of a nonvolatile solute. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer has come to your help. </span>
iragen [17]4 years ago
4 0

Answer:

B.Increase,increase,decreasing

Explanation:

Freezing point:It is defined as the temperature at which the substance freeze.

Vapor pressure: it is defined as the pressure exert by the vapor on the liquid at given temperature and pressure.

Molality:It is defined as the number of moles of solute dissolve in given mass of solvent.

m=\frac{no\;of\;moles\;of\;solute}{mass\;of\;solvent}

When we decrease the freezing point of solution then depression in freezing point increase and then molality of nonvolatile solute is  also increase.

\Delta T_f=i\cdot m\cdot k_f

\Delta T_b=i\cdot m\cdot k_b

When we increase the molality of non volatile solute then elevation in boiling point also increase  and then vapour pressure decrease .

If we decrease molality then elevation in boiling point  and depression in freezing point also decrease.

If elevation in boiling point decrease then vapour pressure increase.

When depression in freezing point decrease then freezing point of solution is increase.

Answer:B.Increase,increase,decreasing

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Determine the number of representative particles in each of the following:
tia_tia [17]

Answer:

(a) 0.294 mol silver = 1.770 * 10^{23}  

(b) 8.98 * 10-3 mol sodium chloride - 5.407 *10^{23}  

(c) 23.3 mol carbon dioxide  = 1.403 * 10^{25}

(d) 0.310 mol nitrogen (N2) = 1.866 * 10^{23}

Explanation:

In one mole there are 6.022 * 10^{23} atoms/molecules

(a) 0.294 mol silver = 6.022 * 10^{23} * 0.294 = 1.770 * 10^{23}  

(b) 8.98 * 10-3 mol sodium chloride - 5.407 *10^{23}  

(c) 23.3 mol carbon dioxide  = 23.3 * 6.022 * 10^{23} = 1.403 * 10^{25}

(d) 0.310 mol nitrogen (N2) = 0.310 * 6.022 * 10^{23} = 1.866 * 10^{23}

3 0
3 years ago
SUSTANTIVO FORMA TAMANO CO
swat32
Please explain more in detail
3 0
4 years ago
24.568 cm of chlorine at 25° C will occupy what volume
Vlad1618 [11]

Answer:

20.446cm3

Explanation:

The following were obtained from the question given:

V1 (initial volume) = 24.568 cm3

T1 (initial temperature) = 25°C = 25 + 273 = 298K

T2 (final temperature) = - 25°C = - 25 + 273 = 248K

V2 (final volume) = ?

Since the pressure is constant, the gas is obeying Charles' law. With the Charles' law equation V1/T1 = V2/T2, we can easily calculate the final volume as follow:

V1/T1 = V2/T2

24.568/298 = V2/248

Cross multiply to express in linear form as shown below:

298 x V2 = 24.568 x 248

Divide both side by 298

V2 = (24.568 x 248) /298

V2 = 20.446cm3

From the calculations made above, the volume of the gas at -25°C is 20.446cm3

5 0
4 years ago
Please answer ASAP,
andrew11 [14]

Answer:

B

Explanation:

I took the test and GOT an A

6 0
3 years ago
The best word to describe how electrons relate to two nuclei in a covalent bond is
ioda
A covalent bond is shared. C
8 0
3 years ago
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