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s2008m [1.1K]
3 years ago
12

Fill in the blanks!

Chemistry
2 answers:
erma4kov [3.2K]3 years ago
7 0
The freezing point of a solution will increase and the vapor pressure will increase with decreasing <span>molality of a nonvolatile solute. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer has come to your help. </span>
iragen [17]3 years ago
4 0

Answer:

B.Increase,increase,decreasing

Explanation:

Freezing point:It is defined as the temperature at which the substance freeze.

Vapor pressure: it is defined as the pressure exert by the vapor on the liquid at given temperature and pressure.

Molality:It is defined as the number of moles of solute dissolve in given mass of solvent.

m=\frac{no\;of\;moles\;of\;solute}{mass\;of\;solvent}

When we decrease the freezing point of solution then depression in freezing point increase and then molality of nonvolatile solute is  also increase.

\Delta T_f=i\cdot m\cdot k_f

\Delta T_b=i\cdot m\cdot k_b

When we increase the molality of non volatile solute then elevation in boiling point also increase  and then vapour pressure decrease .

If we decrease molality then elevation in boiling point  and depression in freezing point also decrease.

If elevation in boiling point decrease then vapour pressure increase.

When depression in freezing point decrease then freezing point of solution is increase.

Answer:B.Increase,increase,decreasing

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Write the balanced chemical equation between H2SO4H2SO4 and KOHKOH in aqueous solution. This is called a neutralization reaction
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0.185M sulfuric acid

Explanation:

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H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

<em>1 mole of sulfuric acid reacts with 2 moles of KOH</em>

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As total volume is 0.700L + 0.750L = 1.450L, concentration is:

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