All categories

3 years ago

Why do we need to know these organic molecules? Are they important to living things?

Chemistry

2 answers:

laila [671]3 years ago

7 0

Answer:

<h2>Organic molecules are important to living things because life is based on the properties of carbon. Carbon is an important element because it can </h2><h2>form four covalent bonds. ... The carbon skeletons contain the functional groups that are involved in biochemical reactions.</h2>

Explanation:

<h2>PLEASE MARK ME BRAINLIEST AND FOLLOW ME LOTS OF LOVE FROM MY HEART AND SOUL DARLING TEJASWINI SINHA HERE ❤️</h2>

saveliy_v [14]3 years ago

7 0

Answer:

Organic molecules are important to living things because life is based on the properties of carbon.

Properties of Carbon

Carbon is an important element because it can form four covalent bonds.

Carbon skeletons can vary in length, branching, and ring structure.

The carbon skeletons contain the functional groups that are involved in biochemical

Explanation:

Hope it helps

You might be interested in

Whoever can answer these for me gets 100 points

tiny-mole [99]

Answer:

The electrons that whiz about outside the nucleus have a negative charge. They are held in the atom by the positive charge of the nucleus. ... An atom that gains or loses an electron becomes an ion. If it gains a negative electron, it becomes a negative ion.

Explanation:

Hope this helped!...

3 0

2 years ago

Read 2 more answers

Calculate the density of a material that has a mass of 50.5g and a volume of 14.5cm3.

White raven [17]

Density = mass / volume = 50.5/14.5 = 3.48 $g/cm ^{3}$ .

4 0

3 years ago

A crime-scene is roped off with yellow tape. The rectangular area is 5.6 meters long 10.75 meters wide. What is the area of the

maksim [4K]

The area is 60.2, to find area it's length times width.

7 0

3 years ago

If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?

ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$ where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation: $T_C+273=T_K$

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, $T_1 = 273[K]$ , and $T_2 = (49.4+273)[K]=322.4[K]$ .

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

$\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}$

$\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})$