Answer:
40.02 calories
Explanation:
V = 10 mL = 10g
we know t went <em>up</em> by 4°C, this is our ∆t as it is a change.
Formula that ties it together: Q = mc∆t
where,
Q = energy absorbed by water
m = mass of water
c = specific heat of water (constant)
∆t = temperature change
Q = (10 g) x (4.186 J/g•°C) x (4°C)
Q = 167.44 J
Joules to Calories:
167.44 J x 1 cal/4.184 J = 40.02 calories
(makes sense as in image it is close to the value).
Explanation:
(a) Formula that shows relation between and
is as follows.
Here, = 1
Putting the given values into the above formula as follows.
=
=
= 0.01316
(b) As the given reaction equation is as follows.
As there is only one gas so ,
= 1.20
Therefore, pressure of in the container is 1.20.
(c) Now, expression for for the given reaction equation is as follows.
=
= \frac{x^{2}}{(a - x)}[/tex]
where, a = initial conc. of
=
= 0.023 M
0.0131 =
x = 0.017
Therefore, calculate the percentage of calcium carbonate remained as follows.
% of remained =
= 75.46%
Thus, the percentage of calcium carbonate remained is 75.46%.
