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3 years ago

Why is a hydraulic system useful?

1 answer:

4 0

Hewoooo!!!

Hydraulics<span> are used in the braking </span>system<span> of a car. They cause a relatively small force from the driver's foot to be multiplied to produce a greater force, which acts equally on all four brake pads. ... The transmitted pressure acts on this larger area to produce a larger load force on the brake pads.

</span>i think they are helpful, it just depends what your using them for :D

You might be interested in

How much force is needed to accelerate a 1000-kg car at a rate of 3 m/s2? a 1003 N b 0.003 N c 3000 N d 333.3 N

Bogdan [553]

Answer:

Option c.

Explanation:

According to Newton's law, formula to solve this problem is:

F = m . a

Mass → 1000 kg

a → 3 m/s²

F = 1000 kg . 3m/s² → 3000 N

1 N = 1 kg . m/s² according to SI, Internation System of units.

7 0

3 years ago

The liter (L) is a measurement of which of the following quantities?

zhenek [66]

Is volume one of your answers?

5 0

3 years ago

Read 2 more answers

Improvements in which area would help reduce the possibility of damage to the environment when using uranium as a fuel?

kogti [31]

Answer:

A is the answer; 'more-efficient extraction techniques

Explanation:

I just took the test and got it right :D

5 0

3 years ago

An open "empty" 2 L plastic pop container, which has an actual inside volume of 2.05 L, is removed from a refrigerator at 5 °C a

Pani-rosa [81]

2.168 L of air will leave the container as it warms

<h3>Further explanation</h3>

Given

V₁=2.05 L

T₁ = 5 + 273 = 278 K

T₂ = 21 + 273 = 294 K

Required

Volume of air

Solution

Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature

$\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

Input the value :

V₂=(V₁.T₂)/T₁

V₂=(2.05 x 294)/278

V₂=2.168 L

3 0

3 years ago

How many liters of O2 at 298 K and 1.00 bar are produced in 1.50 hr in an electrolytic cell operating at a current of 0.0200 A?

stellarik [79]

Answer: 0.0069L

Explanation:

2H2O(l) ---->O2(g) + 4H+(aq) + 4e-

no of moles= it/eF

NO of moles of O2 produced = (Current in Ampere x Time in second)/ (Faraday constant x Number of electrons required)

Moles of O2 produced = (0.02x (60 x 60X1.5 s)/(96485 x 4)

= 0.0002798 moles= 2.798x 10 ^-4moles

Using ideal gas equation,

P V = n R T

Where, P is the pressure,

V is the volume,

n is the number of moles,

R is the gas constant, and T is the temperature

We have, 1 bar = 0.986923 atm

Substituting the values,

V = nRT/P = (2.798 x 10-4moles x 0.08205 L atm mol K x 298 K)/ 0.986923 atm = 0.0069L

Volume of O2 produced = 0.0069L

7 0

3 years ago