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sweet-ann [11.9K]
3 years ago
10

Which step will decrease the pressure of a gas inside a closed cubical container? increasing the number of moles of gas decreasi

ng the volume of the container increasing the speed of the gas particles decreasing the temperature inside the container
Chemistry
2 answers:
Jobisdone [24]3 years ago
8 0

Answer: Decreasing the temperature inside the container will decrease the pressure of a gas inside a closed cubical container.

Explanation:

According to Gay-Lussac's Law : 'The pressure of the gas increases with increase in temperature of the gas when volume of the gas is kept constant'.

(Pressure)\propto (Temperature)

At constant volume, pressure of the gas will decrease on decreasing the temperature or vice versa.

Decreasing the temperature inside the container will decrease the pressure of a gas inside a closed cubical container.

Brums [2.3K]3 years ago
7 0

decreasing the temperature inside the container

hope this helps!

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Lina20 [59]

\huge \fcolorbox{black}{red}{♛answer♛}

Hydrogen Fluoride / HF

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3 0
2 years ago
How do you solve this problem
ad-work [718]

Answer: Volume of gas in the stomach, V = 0.0318L or 31.8mL

Explanation:

The number of moles of oxygen will remain constant even though the liquid oxygen will undergo a change of state to gaseous inside the person's stomach due to an increase in temperature.

<em>Number of moles of oxygen gas = mass/molar mass</em>

molar mass of oxygen gas = 32 g/mol

mass of oxygen gas = density * volume

mass of oxygen gas = 1.149 g/ml * 0.035 ml

mass of oxygen gas = 0.040215 g

Number of moles of oxygen gas = 0.0402 g/(32 g/mol)

Number of moles of oxygen gas = 0.00125 moles

<em>Using the ideal gas equation, PV=nRT</em>

where P = 1.0 atm, V = ?, n = 0.00125 moles, R = 0.082 L*atm/K*mol, T = (37 + 273)K = 310 K

<em>V = nRT/P</em>

V = (0.00125moles) * (0.082 L*atm/K*mol) * (310 K) / 1 atm

V = 0.0318L or 31.8mL

3 0
3 years ago
What should the IUPAC name for a binary covalent compound lack ?
zavuch27 [327]
The answer to the question is "B. Roman Numerals"
5 0
3 years ago
Read 2 more answers
I just started learning about kinetic molecular theory, and I’m not sure how to answer the question circled below
lions [1.4K]

Answer : The value of 'R' is 0.0821\text{ L atm }mol^{-1}K^{-1}

Solution : Given,

At STP conditions,

Pressure = 1 atm

Temperature = 273 K

Number of moles = 1 mole

Volume = 22.4 L

Formula used :     R=\frac{PV}{nT}

where,

R = Gas constant

P = pressure of gas

T = temperature of gas

V = volume of gas

n = number of moles of gas

Now put all the given values in this formula, we get the values of 'R'.

R=\frac{(1atm)\times (22.4L)}{(1mole)\times (273K)}

R=0.0821\text{ L atm }mol^{-1}K^{-1}

Therefore, the value of 'R' is 0.0821\text{ L atm }mol^{-1}K^{-1}.

7 0
3 years ago
Which nuclear decay emission has the weakest penetrating power?
Romashka [77]
Alpha particle is the nuclear decay emission that has the weakest penetrating power. The correct option among all the options that are given in the question is the first option or option "1". Gamma is a type of radiation and so can be negated as a particle. Alpha particles have the largest radiation and so the weakest penetrating power.
3 0
3 years ago
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