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sweet-ann [11.9K]
3 years ago
10

Which step will decrease the pressure of a gas inside a closed cubical container? increasing the number of moles of gas decreasi

ng the volume of the container increasing the speed of the gas particles decreasing the temperature inside the container
Chemistry
2 answers:
Jobisdone [24]3 years ago
8 0

Answer: Decreasing the temperature inside the container will decrease the pressure of a gas inside a closed cubical container.

Explanation:

According to Gay-Lussac's Law : 'The pressure of the gas increases with increase in temperature of the gas when volume of the gas is kept constant'.

(Pressure)\propto (Temperature)

At constant volume, pressure of the gas will decrease on decreasing the temperature or vice versa.

Decreasing the temperature inside the container will decrease the pressure of a gas inside a closed cubical container.

Brums [2.3K]3 years ago
7 0

decreasing the temperature inside the container

hope this helps!

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A gaseous mixture contains 5.0 moles of nitrogen and 10.0 moles of helium . What is the total pressure if the temperature is 25
jolli1 [7]

Answer:

A) 122 atm

Explanation:

PV = nRT

Solve for P --> P = nRT/V

n = 10.0 mol + 5.0 mol = 15.0 mol

R = 0.08206 L atm / mol K

T = 25 + 273 = 298 K

V = 3.0

P = (15.0)(0.08206)(298) / (3.0) = 122 atm

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Answer/Explanation:

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3 years ago
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swat32

Answer:

1461.7 g of AgI

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂

From the balanced equation above,

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Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI

Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:

Mole of AgI = 6.22 moles

Molar mass of AgI = 108 + 127

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Mass = mole × molar mass

Mass of AgI = 6.22 × 235

Mass of AgI = 1461.7 g

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