Answer:
The correct option is;
D. There is not enough information to answer this question
Explanation:
The universal gravitational constant = 6.67408 × 10⁻¹¹ 3³/(kg·s²)
For an in between distance of 1 m and equal masses of 60 kg, we have;
The gravitational attraction ≈ 2.403 × 10⁻⁷ N, which does not correspond with the answers, therefore, the best option is that there is not enough information to answer this question.
The answer is True - but Powell was borrowing from Winston Churchill who originally used this quote to describe Tact.
Answer:
Explanation:
Given data
λ=680nm
L=5.5m
ω=7.9cm=0.079m
To find
Width of slit a
Solution
As the single slit of width a has a bright central maximum of width:
ω=2λL/a
a=2λL/ω
Substitute the given values
So
Answer:
Correct answer: Q = 0.247 μC
Explanation:
Since the oil drop floats, this means that the weight of the drop and the Coulomb force are equal.
F = m · g drop's weight
Fc = k q Q / r² Coulomb force
where it was given:
k = 9 · 10⁹ N m²/C² dielectric constant,
q = 2.2 mC = 2.2 · 10⁻³ C drop's charge,
Q - floor's charge,
r = 7.68 m distance between drop and floor
m = 8.3 grams = 8.3 · 10⁻³ kg drop's weight
and g = 10 m/s²
F = Fc ⇒ k q Q / r² = m · g ⇒ Q = m · g · r²/ k · q
Q = 8.3 · 10⁻³ · 10 · 7.68² / 9 · 10⁹ · 2.2 · 10⁻³
Q = 24.72 · 10⁻⁸ C = 0.2472 · 10⁻⁶ C = 0.2472 μC
Q = 0.247 μC
God is with you!!!
Answer:
B = 4/3 ( i + j + k )
Explanation:
I = 3 k
L = 5 x 10⁻² m
F = - 0.2 i + 0.2 j
Let magnetic field be B
B = B₁ i + B₂ j + B₃ k
F = L ( I x B )
= 5 x 10⁻² 3 k x ( B₁ i + B₂ j + B₃ k )
= 15 x 10⁻² B₁ j - 15 x 10⁻² B₂ i
Given
F = - 0.2 i + 0.2 j
equating equal terms
15 x 10⁻² B₂ = .2
15 x 10⁻² B₁ = .2
B₁ = .02 / 15 x 10⁻² = 20 / 15 N
B₂ = .02 / 15 x 10⁻² = 20 / 15 N
Now wire is rotated so that current flows in positive x direction
I = 3 i
F = . 2 k
F = L ( I x B )
= 5 x 10⁻² x 3 i x ( B₁ i + B₂ j + B₃ k )
= 15 x 10⁻² B₃ k
15 x 10⁻² B₃ = .2
B₃ = .2 /15 x 10⁻²
B₃ = 20 /15
B = B₁ i + B₂ j + B₃ k
20 /15 9 ( i + j + k )
B = 4/3 ( i + j + k )
