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Dmitriy789 [7]
3 years ago
6

4 Points

Physics
2 answers:
Sati [7]3 years ago
6 0

Answer:

Impulse = 322.5[kg*m/s], the answer is D

Explanation:

This method  it is based on the principle of momentum and the amount of movement; and  used to solve problems involving strength, mass, speed and time.

If units of the SI are used, the magnitude of the impulse of a force is expressed in N * s. however, when remembering the definition of the newton.

N*S=(kg*m/s^{2} )*s = kg*m/s

Now replacing the values on the following equation that express the definition of impulse

Impulse = Force * Time\\\\Impulse = 215 * 1.5 = 322.5 [kg*m/s]

snow_lady [41]3 years ago
6 0

Answer:

323 kg*m/s

Explanation:

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borishaifa [10]

Answer:

B

Explanation:

Potential difference has a SI Unit of Volt and its symbol is <em>V</em>. Hence answer is <u>B</u>.

A is wrong as it has the unit Joule <em>(J)</em> which is the SI unit for energy.

C is wrong as it has the unit Newton <em>(N)</em> which is the SI unit for force.

D is wrong as it has the unit Coulomb <em>(C)</em> which is the SI unit of charge.

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4 years ago
How much money would be saved by turning off one 100.0-W lightbulb 3.0 h/day for 365 days if the
Pavlova-9 [17]

Answer:

the money that would be saved is $13.14.

Explanation:

Given;

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cost rate of power consumption, C = $0.12 per kWh

Energy consumed by the light bulb for the given days;

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3 0
3 years ago
If two balls collide with each other, they will move apart at the same speed if
denis-greek [22]
A.
if you have seen a newton's cradle this will make sense.

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7 0
3 years ago
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A 50g ball is released from rest 1.0 above the bottom of thetrack
ludmilkaskok [199]

Answer:

The maximum height of the ball is 2 m.

Explanation:

Given that,

Mass of ball = 50 g

Height = 1.0 m

Angle = 30°

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y=\dfrac{1}{4}x^2

We need to calculate the velocity

Using conservation of energy

\Delta U_{i}+\Delta K_{i}=\Delta K_{f}+\Delta U_{f}

Here, ball at rest so initial kinetic energy is zero and at the bottom the potential energy is zero

\Delta U_{i}=\Delta K_{f}

Put the value into the formula

mgh=\dfrac{1}{2}mv^2

Put the value into the formula

50\times10^{-3}\times9.8\times1.0=\dfrac{1}{2}\times50\times10^{-3}\times v^2

v^2=\dfrac{2\times50\times10^{-3}\times9.8\times1.0}{50\times10^{-3}}

v=\sqrt{19.6}

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Using again conservation of energy

\dfrac{1}{2}mv^2=mgh

Here, h = y highest point

Put the value into the formula

\dfrac{1}{2}\times50\times10^{-3}\times(4.42)^2=50\times10^{-3}\times9.8\times h

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Put the value of y in the given equation

y=\dfrac{1}{4}x^2

x^2=4\times0.996

x=\sqrt{4\times0.996}

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Hence, The maximum height of the ball is 2 m.

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Debora [2.8K]

Answer:

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