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3 years ago

5

John wants a new video tape and a new shirt, but he only has $12.00. He buys the video tape and gets $0.52 change. What was his

opportunity cost?

1 answer:

mestny [16]3 years ago

7 0

Answer:

You have the answer in your comments. I will be copying it so your question doesn't get deleted.

The answers is $0.58

$11.48

the video tape

the new shirt

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A block-and-tackle pulley hoist is suspended in a warehouse by ropes of lengths 2 m and 3 m. the hoist weighs 430 n. the ropes,

ICE Princess25 [194]

Refer to the diagram shown below.

For horizontal equilibrium,
T₃ cos38 = T₂ cos 50
0.788 T₃ = 0.6428 T₂
T₃ = 0.8157 T₂ (1)

For vertical equilibrium,
T₂ sin 50 + T₃ sin 38 = 430
0.766 T₂ + 0.6157 T₃ = 430
1.2441 T₂ + T₃ = 698.392 (2)

Substitute (1) into (2).
(1.2441 + 0.8157) T₂ = 698.392
T₂ = 339.058 N
T₃ = 0.8157(399.058) = 276.571 N

Answer:
T₂ = 339.06 N
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3 years ago

Identify the object that has the largest moment from the list of objects given below.

Luda [366]

Answer:

A fired bullet

Explanation:

A fired bullet is faster than the speed of sound

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The volume of a gas at 400.0ml when the pressure is 1.00atm. at the same temperature, what is the pressure at which the volume o

Mila [183]

Answer:

5.025 atm

Change the 2.01 to ml then cross multiply

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You drop two balls of equal diameter from the same height at the same time. Ball 1 is made of metal and has a greater mass than

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Answer:

The drop time ball 1 is less than the drop time of ball 2. A further explanation is provided below.

Explanation:

The net force acting on the ball will be:

⇒ $F_{net}=mg-F_r$

Here,

F = Force

m = mass

g = acceleration

Now,

According to the Newton's 2nd law of motion, we get

⇒ $F_{net} = ma$

To find the value of "a", we have to substitute " $F_{net}=ma$ " in the above equation,

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3 years ago

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An object of mass 3 kg, moving with and sticks to an object of mass 2.00 kg with an initial velocity of 3.00 m/s. Find the final

Aleonysh [2.5K]

Answer:

1.8 m/s

Explanation:

momentum = mass × velocity

initial momentum = m1v1+m2v2

= 3×3 +2×0 = 9+0= 9 kg m/s

let combined velocity be V

HENCE

final momentum = total mass × velocity

= (3+2) × V = 5V

According to law of conservation of momentum

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V =9/5

V = 1.8 m/s

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3 years ago