Newton's Third Law of Motion states that for every action there must exist an equal but opposite reaction.
This ultimately implies that, Newton's Third Law of Motion is a law based on action-reaction force pairs.
In this exercise, you're required to identify the action-reaction forces in the attached picture.
Under condition A, a boy is leaning against a wall;
- The force being exerted by the boy on the wall is a force of action.
- The force being exerted by the wall on the boy is a force of reaction.
Under condition B, a boy is jumping off a diving board.
- The force being exerted by the feet of the boy on the diving board is a force of action.
- The force being exerted by the diving board on the feet of the boy is a force of reaction.
Under condition C, a nail is being hammered into the wall.
- The force being exerted by the hammer on the nail is a force of action.
- The force being exerted by the nail on the hammer is a force of reaction.
Under condition D, a man is walking on a ground (floor).
- The force being exerted by the foot of the man on the ground (floor) is a force of action.
- The force being exerted by the ground (floor) on the foot of the man is a force of reaction.
Under condition E, a boy is holding a ball;
- The force being exerted by the hand of the boy on the ball is a force of action.
- The force being exerted by the ball on the hand of the boy is a force of reaction.
Read more: brainly.com/question/15170643
Static equilibrium.
Static equilibrium is a kind of equilibrium which occurs when an object is at rest.
Hope this helps!
<span>(a).the heat trasfer surface area and heat flux on the surface of filament are
Area of Surface= µDL=3.14(0.05cm)(5cm)= 0.785 cm square
qs=Q/Area of surface= 150W/0.785= 191W/cmsq.=1.91x10Âłx10ÂłW/Msq
(b). the heat surface on the surface of heat bulb
Area of surface = 3.14xD²= 3.14(8CM)²= 201.1cm²
qs=Q/Area of surface=150w/201.1cm²=0.75 w/cm²= 7500w/m²
the amount and cost of electrical energy consumed during one period is
Electrical Consumption=QΛt=(0.15 KW)(365X8h/yr)=438 k Wh/yr
Annual cost= 438 kWh/yr)($.08/kWh)= $ 35.04 /yr</span>
The solution for the problem is:
The pressure of a column of fluid = rho g h
Where: rho = density,
g = 9.81m/s/s, and
h = depth
at 10.92km:
P = 1027kg * 9.81m/s/s * 10920 m
= 1027 kg x 107125.2
= 1.10 x 10^8 Pa (the MKS unit of pressure)
Their has to be a set amount of temperature From the beginning
(Either be it 0 or 'n' (n stands for any #))
Then you would find if you have to make the temperature increase or decrease.
