Can someone please help, ty!! (Will mark brainliest)

What earthquake damage is Texas likely to suffer

kumpel [21]

-- Most of the southern part of the state is considered to have
no risk of damage.

-- Most of the upper part of the state is considered to be at risk
for only minor damage.

-- A tiny part of the state, in the 'Big Bend' region in the west, is
considered to be at risk for moderate damage.

3 0

3 years ago

Read 2 more answers

What is the speed of a 200-kilogram car that is driving with 2000 joules of kinetic energy? (SHOW ALL WORK)

Katyanochek1 [597]

Answer:

v ≈ 4.47

Explanation:

The Formula needed = KE = $\frac{1}{2}$ m v²

Substitute with numbers known:

2000J = $\frac{1}{2}$ × 200kg × v²

Simplify:

÷100 ÷100 (Divide by 100 on both sides)

2000J = 100 × v²

$\frac{2000J}{100}$ = v²

20 = v²

√ √ (Square root on both sides)

√20 = √v²

4.472135955 = v (Round to whatever the question asks)

v ≈ 4.47 (I rounded to 2 decimal places or 3 significant figures, as that is what it usually is)

3 0

3 years ago

Pure water has a pH of 7. Pure water _______. A. is a neutral substance B. could be either an acid or a base C. is a base D. is

malfutka [58]

A. is a neutral substance.

Only neutral substances (like pure water) can have a pH of 7.

5 0

3 years ago

Read 2 more answers

A gas undergoes two processes. In the first, the volume remains constant at 0.170 m3 and the pressure increases from 1.50×105 Pa

Mnenie [13.5K]

Answer:

$W_{T} = - 24 kJ$

Explanation:

The work (W) done by the gas can be calculated using the following equation:

$W = p*\Delta V = p*(V_{f} - V_{i})$

Where:

p: is the pressure

[tex}V_{f}[/tex]: is the final volume

[tex}V_{i}[/tex]: is the initial volume

In the first process, the work done by the gas is:

$W_{1} = p*\Delta V = p*0 = 0$

Since the volume remains constant, the total work done by the gas is equal to zero.

In the second process, the work done by the gas is:

$W_{2} = p*(V_{f} - V_{i}) = 6.00 \cdot 10^{5} Pa*(0.130 m^{3} - 0.170 m^{3}) = -24 kJ$

Now, the total work done by the gas during both processes is:

$W_{T} = W_{1} + W_{2} = 0 + (-24 kJ) = - 24 kJ$

Therefore, the total work done by the gas during both processes is - 24 kJ.

I hope it helps you!

7 0

4 years ago

What would the potential of a standard hydrogen electrode (s.h.e.) be under the given conditions? [h+]=0.70 mph2=2.4 atmt=298 k?

Andru [333]

Constant = 8.314JK⁻¹mol⁻¹
T is for temperature which is 298K
Faraday constant value is 96500C/mol
n is the number of electrons which are transferred in the reaction.
Ecell = E₀cell - RT/nFiN [cathode]/[anode]
Ecell = E₀cell - RT/nF In [PH₂]/[H⁺]²
Ecell = 0.00-8.314 JK⁻¹ mol⁻¹ × 298k/ 2× 96500C/mol In [2.4atm]/ 0.70]²
Ecell = 0.00 - 0.0129 In (2.59)
Ecell = 0.00 - 0.0129 × 0.951
Ecell = -0.0122V
∴Ecell is = -o.0122v

7 0

3 years ago