Light as a wave
- Young's Double Slit Experiment.
- Davisson-Germer Experiment
Light as a particle
- Einsteins Photoelectric Effect Phenomenon
- Diffraction Phenomenon of Particles
<h2>Define the following terms:-</h2><h3>
1)Photoelectric Effect</h3>
Electrons are released when a material is exposed to electromagnetic radiation, such as light, and this is known as the photoelectric effect. These electrons are referred to as photoelectrons.
<h3>
2)Diffraction </h3>
When a wave hits a wall or an opening, several phenomena known as diffraction take place. It is described as the interference or bending of waves through an aperture into the region of the geometric shadow cast by the obstruction or aperture.
<h3>3)
Davisson-Germer Experiment</h3>
In the Davisson-Germer experiment, conducted by Clinton Davisson and Lester Germer between 1923 and 1927 at Western Electric (later Bell Labs), electrons scattered by a nickel-metal crystal's surface showed a diffraction pattern. This was an experimental turning point in the development of quantum mechanics and supported the wave-particle duality concept first put forth by Louis de Broglie in 1924.
<h3>4)
Young's Double Slit Experiment.</h3>
One of the most significant physics experiments was Young's Double Slit experiment. Thomas Young directed it in 1801. Despite the fact that Huygens' experiment had demonstrated that light has a wave character, the light at the time was still thought of as a beam of particles due to Newton's renown.
Learn more about the photoelectric effect here:-
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Was there supposed to be a picture?
For a reaction rate that increases by a factor of 655 in the presence of a catalyst at 37°C, the activation energy of the new pathway is mathematically given as
Ea2=89.28JKoule/mol
<h3>What is the activation energy of the new pathway, all other factors being equal?</h3>
Generally, the equation for the rate constant is mathematically given as
K=Ae^{Ea1/Rt}
Therefore
Ea2=89286.083Joule/mol
In conclusion, the activation energy
Ea2=89.28JKoule/mol
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Answer:
The trans/trans stereoisomer.
Explanation:
So, we are going to have two stereoisomers or arrangements for this chemical compound, that is the Cis/trans, the trans/trans.
For a compound to be seen with UV, the main or primary condition is conjugation or how conjugated the chemical specie or compound is.
Thus, the more the conjugation, the more or the higher the wavelength or lands value.
=> The Trans/trans stereoisomer will have the highest lamda value or wavelength because the energy gap in its π - π* Transitioning deceases due to the STERIC interactions, and the more the decrease in the energy gap, the more or the higher the lamda value or wavelength.
