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Tatiana [17]
3 years ago
5

I WILL GIVE EXTRA POINTS AND BRAINLIEST I JUST NEED SOMEONE TO ANSWER THIS QUESTIONS!!

Chemistry
2 answers:
olga nikolaevna [1]3 years ago
8 0

Answer:

A

Explanation:

Rufina [12.5K]3 years ago
8 0
The answer is A I think
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A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati
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First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

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a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

k=\frac{2.303}{48.0}\log\frac{53500}{42520}

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Now we have to calculate the half-life.

k=\frac{0.693}{t_{1/2}}

9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}

t_{1/2}=6.94hr

Therefore, the half life of 28-Mg in hours is, 6.94

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