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Elodia [21]
3 years ago
6

The volume of a ball was measured at 500.0 cm?, and its mass was measured to be 404.2 g.

Chemistry
1 answer:
Burka [1]3 years ago
8 0

Answer:

0.8084g/cm³

Explanation:

Density of a substance is calculated as follows:

Density = mass/volume

According to this question, the volume of a ball was measured at 500.0 cm³ and its mass was measured to be 404.2g. The density is this:

Density (P) = 404.2/500

Density = 0.8084

Density of the ball = 0.8084g/cm³

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Does a high melting point mean the substance will melt faster or slower?
user100 [1]

Answer:

slower...............

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5 0
2 years ago
Read 2 more answers
As you go down group one of the periodic table, the reactions become and more
Lady bird [3.3K]

Answer:

vigorous

Explanation:

As you go down group one of the periodic table, the reactions become and more vigorous.

3 0
2 years ago
How many mL of 0.715 M HCl is required to neutralize 1.25 grams of sodium carbonate? (producing carbonic acid)
jonny [76]

Answer:

34 mL

Explanation:

We'll begin by calculating the number of mole in 1.25 g of sodium carbonate, Na₂CO₃. This can be obtained as follow:

Mass of Na₂CO₃ = 1.25 g

Molar mass of Na₂CO₃ = (23×2) + 12 + (16×3)

= 46 + 12 + 48

= 106 g/mol

Mole of Na₂CO₃ =?

Mole = mass /molar mass

Mole of Na₂CO₃ = 1.25 / 106

Mole of Na₂CO₃ = 0.012 mole

Next, we shall determine the number of mole HCl needed to react with 0.012 mole of Na₂CO₃.

The equation for the reaction is given below:

Na₂CO₃ + 2HCl —> H₂CO₃ + 2NaCl

From the balanced equation above,

1 mole of Na₂CO₃ reacted with 2 moles of HCl.

Therefore, 0.012 mole of Na₂CO₃ will react with = 0.012 × 2 = 0.024 mole of HCl.

Next, we shall determine the volume of HCl required for the reaction. This is illustrated:

Mole of HCl = 0.024 mole

Molarity of HCl = 0.715 M

Volume of HCl =?

Molarity = mole /Volume

0.715 = 0.024 / volume of HCl

Cross multiply

0.715 × volume of HCl = 0.024

Divide both side by 0.715

Volume of HCl = 0.024 / 0.715

Volume of HCl = 0.034 L

Finally, we shall convert 0.034 L to mL

This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.034 L = 0.034 L × 1000 mL / 1 L

0.034 L = 34 mL

Therefore, 34 mL of HCl is needed for the reaction.

6 0
2 years ago
The net force on a vehicle that is accelerating at a rate of 1.2 m/s² is 1500 newtons. What is the mass
kotegsom [21]

Answer:

1250kg

Explanation:

Given parameters:

Acceleration  = 1.2m/s²

Force  = 1500N

Unknown:

Mass on the vehicle  = ?

Solution:

According to newton's second law of motion:

  Force  = mass x acceleration

Since mass is the unknown, insert the parameters and solve;

       1500  = mass x 1.2

        mass = \frac{1500}{1.2}   = 1250kg

5 0
2 years ago
What is the molarity of an HCl solution if 125 mL is neutralized in a titration by 76.0 mL of 1.22 M KOH?
Lunna [17]

Answer:

0.74176 M HCl

Explanation:

1) Write out a balanced equation.

  KOH + HCl --> KCl + H2O

2) Calculate #mol KOH in 76.0mL needed for the titration.

 1.22 mol KOH in 1000mL

 x mol KOH in 76.0mL

 x = 0.09272 mol KOH

3) Use the balanced equation ratio (from step 1), 1 mol KOH : 1 mol HCl.

0.09272 mol KOH = 0.09272 mol HCl

4) 125mL of the HCl solution was used for the titration, so find the molarity.

0.09272 mol HCl is in 125mL

x mol HCl in 1000mL

x = 0.74176 mol HCL / 1 L

SO... 0.74176 M HCl is the answer.

*hope this helped*

- A Kind Stranger

4 0
2 years ago
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