Structure can affect the Ka values for related acids. In the boxes below, draw the complete Lewis structure for a single ion of
the conjugate base of each acid after the removal of a proton and consider the change in stability of the ion resulting from deprotonation. HINTS: Consider any increase/decrease in ability to participate in intramolecular hydrogen bonding as well as how the resulting –COO- groups in a molecule will interact with other atoms in the same molecule/ion.
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<u>Answer:</u> The value of equilibrium constant for the net reaction is 11.37
<u>Explanation:</u>
The given chemical equations follows:
<u>Equation 1:</u>
<u>Equation 2:</u>
The net equation follows:
As, the net reaction is the result of the addition of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the inverse of second equilibrium constant.
The value of equilibrium constant for net reaction is:
We are given:
Putting values in above equation, we get:
Hence, the value of equilibrium constant for the net reaction is 11.37