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Tju [1.3M]
3 years ago
10

Structure can affect the Ka values for related acids. In the boxes below, draw the complete Lewis structure for a single ion of

the conjugate base of each acid after the removal of a proton and consider the change in stability of the ion resulting from deprotonation. HINTS: Consider any increase/decrease in ability to participate in intramolecular hydrogen bonding as well as how the resulting –COO- groups in a molecule will interact with other atoms in the same molecule/ion.

Chemistry
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

Explanation: see attachment below

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How would you prepare 3.5 L of a 0.9M solution of KCl?
PolarNik [594]
V=3,5L\\
Cm=0,9M\\
M_{KCl}=74\frac{g}{mol}\\\\
C_{m}=\frac{n}{V}\\\\
n=\frac{m}{M}\\\\
C_{m}=\frac{m}{MV} \ \ \ \Rightarrow  \ \ \ m=C_{m}MV\\\\
m=0,9\grac{mol}{L}*74\frac{g}{mol}*3,5L=233,1g

B. Add 233 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark. 
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3 years ago
Which of the following is an example of a model? PV=nRT, Geographical map, I believe that aliens exist, all of the above.
aleksandrvk [35]

<u>Answer:</u> The correct answer is geographical map.

<u>Explanation:</u>

Model is defined as the three dimensional representation of a proposed structure in a smaller scale.

For the given options:

<u>Option 1:</u>  PV = nRT

This is a proposed law. This law is known as ideal gas law. A law is defined as the rule which defined a correct procedure. For any gas behaving ideally, this law is used.

<u>Option 2:</u> Geographical map

Map is defined as the diagrammatic representation of an area of land or sea which also shows physical features, roads, cities etc..

A 3-D model can be prepared for geographical map.

<u>Option 3:</u> I believe that aliens exist

This is a hypothetical statement. It is a smart guess by the means of set of assumptions and observations. For its validation, we need to conduct some experiments.

Hence, the correct answer is geographical map.

3 0
2 years ago
Read 2 more answers
What is the enthalpy of combustion (per mole) of C4H10 (g)? 
Artemon [7]
The balanced chemical reaction for the complete combustion of C4H10 is shown below:

                    C4H10 + (3/2)O2 --> 4CO2 + 5H2O

The enthalpy of formation are listed below:
          C4H10: -2876.9 kJ/mol
              O2:   none (because it is pure substance)
             CO2: -393.5 kJ/mol
             H2O: -285.8 kJ/mol

The enthalpy of combustion is computed by subtracting the total enthalpy formation of the reactants from that of the products.

               ΔHc = (4)(-393.5 kJ/mol) + (5)(-285.8 kJ/mol) - (-2876.9 kJ/mol)
                       = -<em>126.1 kJ</em>

Thus, the enthalpy of combustion of the carbon is -126.1 kJ. 
5 0
2 years ago
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An analytical chemist weighs out 0.055g of an unknown triprotic acid into a 250mL volumetric flask and dilutes to the mark with
Katarina [22]

Answer:

Mass of the unknown acid is 4.0g

Explanation:

The determine the molar mass of the unknown acid, the steps below can be followed

Firstly, determine the concentration of the acid, the formula below can be used;

ConcA × Va/ConcB × Vb = Na/Nb

Where ConcA is the concentration of the unknown acid

ConcB is the concentration of the NaOH base

Va is the volume of acid and Vb is the volume of base

Since, the titration was said to have reached an equivalent point, it means the number of moles of the acid (Na) was equal to the number of moles of the base (Nb) and thus both will be assumed to be 1

Thus

ConcA × 250/0.13 × 6.6 = 1/1

ConcA = 0.13 × 6.6/250

ConcA = 0.003432M

Then, determine the actual number of moles (n) of the unknown acid used,

ConcA = no of moles of acid/volume of acid (in dm³ or L)

To convert mL to L, we divide by 1000

Hence, 250ml = 0.25L

0.003432 = n/0.25

n = 0.003432 × 0.25

n = 0.01373 moles

To determine the molar mass;

n = mass/molar mass

The mass was given in the question to be 0.055g

Thus

0.01373 = 0.055/molar mass

molar mass = 0.055/0.01373

molar mass = 4.0g

5 0
2 years ago
Which of the following are properties of metalloids?
harkovskaia [24]

Answer:

all of these are properties of metalloids

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2 years ago
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