Answer:
2.58 m/s
Explanation:
We can use the following equation of motion to find out the constant acceleration of the block:
where v = 3.8 m/s is the final velocity after it has traveled 7.4 m, is the initial velocity of the block when it starts from rest, , and is the distance traveled.
We can use the same motion equation to calculate block speed at the end of 3.4m track
Answer:
see below
Explanation:
according to newton's second law of motion,
F = MA
where F is the resultant force
m is the mass
a = acceleration
so suppose the mass of the bowling ball is 10 kg
and the mass of golf ball is 1 kg
and the force applied on both of them is 5 N
substitute the values in the formula
for the bowling ball
5 = 10 x a
a = 0.5 ms²
for the golf ball
5 = 1 x a
a = 5 ms²
so which accelerated more the golf ball right?
so last option is the answer
hope this helps,
please mark it brainliest if helpful
Answer:
The answer to your question is:
a) t = 3.81 s
b) vf = 37.4 m/s
Explanation:
Data
height = 71.3 m = 234 feet
t = 0 m/s
vf = ?
vo = 0 m/s
Formula
h = vot + 1/2gt²
vf = vo + gt
Process
a)
h = vot + 1/2gt²
71.3 = 0t + 1/2(9.81)t²
2(71.3) = 9,81t²
t² = 2(71.3)/9.81
t² = 14.53
t = 3.81 s
b)
vf = 0 + (9.81)(3.81)
vf = 37.4 m/s