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Pani-rosa [81]
3 years ago
11

In scientific notation, 474,000 is written:

Physics
1 answer:
ioda3 years ago
4 0

Answer:

The answer is 4.74 × 10⁵

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Explain what parallel medium boundaries do to the path of the wave after it travels through both boundaries. (air and water)
Brilliant_brown [7]

Answer:

The boundaries cause the waves to change direction an effect called <u>refraction.</u>

Explanation:

When a wave crosses a boundary between different materials, the speed of the wave and its wavelength changes.When passing from air to water the two properties (speed and wavelength) decreases, and the wave is observed to change direction as it crosses the boundary between the two material.The bending of the wave is called refraction.

7 0
3 years ago
Can kintic friction affect mechanical energy
Nesterboy [21]
Yes. Kinetic energy is a form of mechanical energy and friction will turn that kinetic energy into heat.
3 0
3 years ago
A river 1.00 mile wide flows with a constant speed of 1.00 mph. A man can row a boat at 2.00 mph. He crosses the river in a dire
gladu [14]

To solve this problem we will apply the geometric concepts of displacement according to the description given. Taking into account that there is an initial displacement towards the North and then towards the west, therefore the speed would be:

V_T^2=v_N^2-v_W^2

V_T = \sqrt{v_N^2-v_W^2}

Travel north 2mph and west to 1mph, then,

V_T = \sqrt{2^2-1^2}

V_T = \sqrt{3}

The route is done exactly the same to the south and east, so make this route twice, from the definition of speed we have to

v= \frac{\Delta x}{t}

t = \frac{\Delta x}{v}

t = \frac{2*(1mile)}{\sqrt{3}mph}

t = 1.15hour

Therefore the total travel time for the man is 1.15hour.

3 0
3 years ago
A 0.683 kg mass moves in SHM at the end of a spring. It takes 1.41 s to move from the position with the spring fully extended to
dsp73

Answer:

Spring constant of the spring will be equal to 9.255 N /m          

Explanation:

We have given mass m = 0.683 kg

Time taken to complete one oscillation is given T = 1.41 sec

We have to find the spring constant of the spring

From spring mass system time period is equal to T=2\pi \sqrt{\frac{m}{K}}, here m is mass and K is spring constant

So 1.41=2\times 3.14\sqrt{\frac{0.683}{K}}

0.2245=\sqrt{\frac{0.683}{K}}

Squaring both side

0.0504=\frac{0.4664}{K}

K=9.255N/m

So spring constant of the spring will be equal to 9.255 N /m

7 0
3 years ago
Can work done=mass*acceleration*displacement(work=m*a*s)
Airida [17]

no, work is = force * distance or displacement


5 0
4 years ago
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