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Advocard [28]
3 years ago
6

On a balanced seesaw, a boy three times as heavy as his partner sits

Physics
1 answer:
slega [8]3 years ago
8 0

Answer:

1/3 the distance from the fulcrum

Explanation:

On a balanced seesaw, the torques around the fulcrum calculated on one side and on another side must be equal. This means that:

W_1 d_1 = W_2 d_2

where

W1 is the weight of the boy

d1 is its distance from the fulcrum

W2 is the weight of his partner

d2 is the distance of the partner from the fulcrum

In this problem, we know that the boy is three times as heavy as his partner, so

W_1 = 3 W_2

If we substitute this into the equation, we find:

(3 W_2) d_1 = W_2 d_2

and by simplifying:

3 d_1 = d_2\\d_1 = \frac{1}{3}d_2

which means that the boy sits at 1/3 the distance from the fulcrum.

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Complete Question

The complete question is shown on the first uploaded image

Answer:

The time taken  is  t  = 6.89 \ hrs

 

Explanation:

From the question we are told that

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                 \int\limits \frac{du}{u-T}  =\int\limits   - kdt

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Hence

        u_t =  11 + 59 e^{-0.15 *t}

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=>     t  =  -\frac{ln(\frac{21}{59} )}{0.15}

         t  = 6.89 \ hrs

 

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Answer:

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b.  this force compare to the weight of the muon; the force is 1.38 × 10⁸ greater than muon

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