Engineers design a system for heating the air in a house. They want the
1 answer:
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Answer:
D) Q/2
Explanation:
The relationship between charge Q, capacitance C and voltage drop V across a capacitor is
(1)
In the first part of the problem, we have that the charge stored on the capacitor is Q, when the voltage supplied is V. The capacitance of the parallel-plate capacitor is given by
where is the vacuum permittivity, A is the area of the plates, d is the separation between the plates.
Later, the voltage of the battery is kept constant, V, while the separation between the plates of the capacitor is doubled: . The capacitance becomes
And therefore, the new charge stored on the capacitor will be
Answer:
W=0.94J
Explanation:
Electrostatic potential energy is the energy that results from the position of a charge in an electric field. Therefore, the work done to move a charge from point 1 to point 2 will be the change in electrostatic potential energy between point 1 and point 2.
This energy is given by:
So, the work done to move the chargue is:
The work is positive since the potential energy in 1 is greater than 2.