Answer: Graphing data is used to display data because it is easier to see trends in the data when it is displayed visually compared to when it is displayed numerically in a table.
Answer:
Acceleration due to gravity will be 
Explanation:
We have given gauge pressure P = 3.8 atm = 3.8×101325 = 385035 Pa
Depth h = 24.3 m
Density 
We have find the acceleration due to gravity at the surface of planet
We know that pressure is given by

So 

Acceleration due to gravity will be 
Answer:
Explanation:
We shall apply work energy theorem to calculate the initial velocity just after the collision .
Their kinetic energy will be equal to work done by friction .
force of friction = μ mg , where μ is coefficient of friction , m is total mass and g is acceleration due to gravity
force = .463 x 3210 x 9.8
= 14565.05 N
work done = force x displacement
= 14565.05 x 14.54 = 211775.88 J
now applying work energy theorem
1/2 m v² = 211775.88 , m is composite mass , v is velocity just after the collision
.5 x 3210 x v² = 211775.88
v² = 131.94
v 11.48 m /s
Answer:
The radius described the proton moving is
r=3.91mm
Explanation:
The magnetic field that moving the proton with the velocity
v=15 km/s
To find the radius combinate the magnetic field with the mass of the proton and the charge of the proton
r = mv=eB
r = mv/eB

r = 3.9mm