Answer:
The speed of the stone when it is 4.66 m higher is 236.057 m/s.
Explanation:
Given the initial velocity and vertical distance, we can use the fourth kinematic equation (
) to find v final, or the v to the left of the equal sign. We know 
(initial velocity) is 24.7 m/s, y (change in vertical distance) is 4.66 m, and a is another way to write g (acceleration due to gravity), or 9.8 
.
From here you could plug in the values and solve for v final, but to make the solving process simpler, we can simplify the given equation, <em>then </em>plug in the known values.
To isolate v final, we can take the square root of 
and do the same to the right side of the equation. Therefore, we can find v final with: 
, where v initial is outside of the square root because it squared...
If we plug in the known values to the simplified equation, we get: 
The final answer is 236.057 m/s.
The condition for maximum intensity is the same as that for a double slit. However, angular separation of the maxima is generally much greater because the slit spacing is so small for a diffraction grating. For a diffraction grating with lines/mm = lines/inch, the slit separation is d = micrometers = x10^ m.
The answer to your question is D. barred spiral
Hope I could help! :)
Answer:
(a) x=ASin(ωt+Ф₀)=±(√3)A/2
(b) x=±(√2)A/2
Explanation:
For part (a)
V=AωCos(ωt+Ф₀)⇒±0.5Aω=AωCos(ωt+Ф₀)
Cos(ωt+Ф₀)=±0.5⇒ωt+Ф₀=π/3,2π/3,4π/3,5π/3
x=ASin(ωt+Ф₀)=±(√3)A/2
For part(b)
U=0.5E and U+K=E→K=0.5E
E=K(Max)
(1/2)mv²=(0.5)(1/2)m(Vmax)²
V=±(√2)Vmax/2→ωt+Ф₀=π/4,3π/4,7π/4
x=±(√2)A/2
