1. What is the frequency of light having a wavelength of 406 nm?

Chemistry

1 answer:

morpeh [17]3 years ago

4 0

Answer:

1. frequency = 7.39 * 10¹⁴ Hz

2. wavelength = 1.44 * 10⁸ nm

Explanation:

The speed, frequency and wavelength of waves are related by the formula;

speed = wavelength * frequency

1. wavelength of light = 406 nm = 4.06 * 10⁻⁷ m

speed of light is a constant = 3.0 * 10⁸ m/s

From the formula above, frequency = speed / wavelength

therefore, frequency = (3.0 * 10⁸ m/s) / 4.06 * 10⁻⁷ m

frequency = 7.39 * 10¹⁴ Hz

2. From the equation above, wavelength = speed/frequency

speed of radiation = 3.0 * 10⁸ m/s

frequency = 2.09 * 10⁹ Hz or 2.09 * 10⁹ s⁻¹

therefore, wavelength = (3.0 * 10⁸ m/s) / 2.09 * 10⁹ s⁻¹

wavelength = 1.44 * 10⁸ nm

You might be interested in

present day india is in south asia at the northern end of the indian ocean what evidence found in india matches that of other lo

alekssr [168]

Answer:

Lystrosaurus fossils are just found in Antarctica, India, and South Africa. Like the land abiding Cynognathus, the Lystrosaurus would have not had the swimming capacity to navigate any sea. Advanced portrayal of the Glossopteris. Potentially the main fossil proof found is the plant, Glossopteris.

Explanation:

Hope it helps

5 0

3 years ago

In the endothermic reaction below, how would adding heat affect the equilibrium of the system? (2 points)

seropon [69]

The answer will be B

6 0

3 years ago

For the skeletal chemical equation BF3(g) + NaH(s) → B2H6(g) + NaF(s) what is the coefficient of B2H6 in the balanced equation?

KonstantinChe [14]

Answer:

Coefficient in front of the $B_2H_6$ in the balanced equation - 1

Explanation:

The unbalanced Chemical equation is shown below as:-

$BF_3+NaH\rightarrow B_2H_6+NaF$

On the left hand side,

There are 1 boron atom and 3 fluorine atoms and 1 sodium and hydrogen atoms.

On the right hand side,

There are 2 boron atoms and 6 hydrogen atoms and 1 sodium and fluorine atoms.

Thus,

leftside, $BF_3$ must be multiplied by 2 to balance boron and right side, $NaF$ must be multiplied by 6 to balance fluorine. Left side, $NaH$ must be multiplied by 6 to balance sodium and hydrogen atoms.