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mr Goodwill [35]
3 years ago
8

Do metals form are anions or cations?

Chemistry
1 answer:
goldfiish [28.3K]3 years ago
5 0

Answer: Metals form cations.

The alkali metals (the IA elements) lose a single electron to form a cation with a 1+ charge.

The alkaline earth metals (IIA elements) lose two electrons to form a 2+ cation.

Aluminum, a member of the IIIA family, loses three electrons to form a 3+ cation.

Therefore, metals in the s and p block of the periodic table have 1, 2 or 3 electrons in their outermost orbit (or valence shell). Now to gain a stable octet metals lose either 1, 2 or 3 electrons from the valence shell thus forming cation with +1, +2 or +3 charge.

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I know this one it’s B
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Name the element described in each of the following:
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A collection of elements in a group share chemical properties.

What is Periodic Table?

The elements are arranged in groups and periods on the periodic table. There is a great deal of chemical similarity between the elements in the same group. Only the number of valence shells is the same for elements that belong to the same period.

Each statement refers to the following elements:

(a) Smallest atomic radius in Group 6A(16) - oxygen

(b) Largest atomic radius in Period 6 - cesium

(c) Smallest metal in Period 3 - Aluminium

(d) Highest IE₁ in Group 4A(14) - carbon

(e) Lowest IE₁ in Period 5 -  Bismuth

(g) Group 3A(13) element that forms the most basic oxide -  Thallium

(h) Period 4 element with filled outer level - krypton

(i) Condensed ground-state electron configuration of [Ne] 3s²3p² - silicon

(j) Condensed ground-state electron configuration of [Kr] 5s²4d⁶- xenon

(k) Forms 2+ ion with electron configuration [Ar] 3d³ - vanadium

(l) Period 5 element that forms 3+ ion with pseudo–noble gas configuration - Indium

(m) Period 4 transition element that forms 3+ diamagnetic ion - Scandium

(n) Period 4 transition element that forms 2+ ion with a halffilled d sublevel - Manganese

(o) Heaviest lanthanide - Lutetium

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(q) Alkaline earth metal whose cation is isoelectronic with Kr - Strontium

(r) Group 5A(15) metalloid with the most acidic oxide - nitrogen

To learn more about periodic table click on the link below:

brainly.com/question/569321

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4 0
2 years ago
Can someone pls tell me if this is right?
Sholpan [36]

Answer:

wrong it is hydrogen is more electronegative

you are welcome

5 0
3 years ago
Susan was investigating which glue would make the strongest craft stick tower. She
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Answer:

<u>glue that would make the strongest craft stick tower.</u>

Explanation:

<u>Independent variable: </u>In statistics and research methods, the term "independent variable" is determined as a variable that is being changed, controlled, or altered in an experiment or research by the researcher or the experimenter to see its effect on DV or dependent variable. However, it is said that independent variable directly effect the dependent variable.

6 0
3 years ago
The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wave
timofeeve [1]

Explanation:

It is given that,

The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wavelength 3745 nm. It means that,

n_i=8

\lambda=3745\ nm

The amount of energy change during the transition is given by :

\Delta E=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

And

\dfrac{hc}{\lambda}=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

Plugging all the values we get :

\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3745\times 10^{-9}}=2.179\times 10^{-18}[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\\dfrac{5.31\times 10^{-20}}{2.179\times 10^{-18}}=[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\0.0243=[\dfrac{1}{n_f^2}-\dfrac{1}{64}]\\\\0.0243+\dfrac{1}{64}=\dfrac{1}{n_f^2}\\\\0.039925=\dfrac{1}{n_f^2}\\\\n_f^2=25\\\\n_f=5

So, the final level of the electron is 5.

4 0
3 years ago
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