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OLga [1]
3 years ago
11

If you push a 900N refrigerator with the same force as you lift a 40N dumbbell, the dumbbell will move faster. Which of Newton’s

laws is this an example of? Explain how you know.
Physics
1 answer:
svetlana [45]3 years ago
3 0

This is Newton's second law of motion.

It states that Force exerted on a moving object is directly proportional to its product of mass and acceleration.

i.e Force(F) = Mass(M) × Acceleration(A)

Because Force is constant here, reducing the weight of the body the force is applied to consequently reduces its mass.

If mass is reduced, the body's acceleration increases hence increasing its speed.

That is why the 40N dumbbell move faster.

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A horizontal insulating rod of length 11.8-cm and charge 19 nC is in a plane with a long straight vertical uniform line charge.
SCORPION-xisa [38]

Answer:

11.962337 × 10^-4 N

Explanation:

Given the following :

Length L = 11.8

Charge = 29nC = 29 × 10^-9 C

Linear charge density λ = 1.4 × 10^-7 C/m

Radius (r) = 2cm = 2/100 = 0.02 m

Using the relation:

E = 2kλ/r ; F =qE

F = 2kλq/L × ∫dr/r

F = 2*k*q*λ/L × (In(0.02 + L) - In(0.02))

2*k*q*λ/L = [2 × (9 * 10^9) * (29 * 10^9) * (1.4 * 10^-7)]/ 0.118] = 6193.2203 × 10^(9 - 9 - 7) = 6193.2203 × 10^-7 = 6.1932203 × 10^-4

In(0.02 + 0.118) - In(0.02) = In(0.138) - In(0.02) = 1.9315214

Hence,

(6.1932203 × 10^-4) × 1.9315214 = 11.962337 × 10^-4 N

3 0
4 years ago
a 282 kg bumper car moving right at 3.50 m/s collides with a 155 kg bumper car moving 1.88 m/s left. afterwards, the 282 kg car
Vaselesa [24]

The momentum of the 155 kg car afterwards is 469.7 kg m/s to the right

Explanation:

We can solve the problem by using the law of conservation of momentum: the total momentum of the system is conserved before and after the collision, so we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 282 kg is the mass of the bumper car

u_1 = 3.50 m/s is the initial velocity of the bumper car (we take the right as positive direction)

v_1 = 0.800 m/s is the final velocity of the bumper car

m_2 = 155 kg is the mass of the second bumper car

u_2 = -1.88 m/s is the initial velocity of the second car (moving to the left)

v_2 is the final velocity of the second car

Solving for v_2,

v_2 = \frac{m_1 u_1+m_2 u_2 - m_1 v_1}{m_2}=\frac{(282)(3.50)+(155)(-1.88)-(282)(0.800)}{155}=3.03 m/s

where the positive sign means the direction is to the right.

And now we can find the momentum of the 155 kg afterwards, which is

p_2 = m_2 v_2 = (155)(3.03)=469.7 kg m/s (to the right)

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

7 0
3 years ago
Which statements belong to dalton's atomic theory? select all that apply
kvv77 [185]

The answers would be:

3. Atoms cannot be broken down into smaller pieces (or indivisible)

4. All atoms of an element are identical.

5. Chemical reactions cause atoms to be rearranged.

Although all of the statements regarding atoms are true, because of the technology during Dalton's time, the others were not yet discovered. As time progressed modifications were made which built our modern atomic theory.

3 0
3 years ago
Read 2 more answers
What is Not an example of an machanical wave
Juli2301 [7.4K]

Answer:

Definitely without a doubt a pumpkin

6 0
3 years ago
Read 2 more answers
What average force is required to stop an 1100-kg car in 8.0s if the car is travelling at 95km/h?
Semenov [28]

Answer: 13062.5 N

What average force is required to stop an 1100-kg car in 8.0 s if it is traveling at 95 km/h? i got the answer to be 13062.

6 0
3 years ago
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