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4 years ago

Gina rolled a ball down a hill.

Physics

1 answer:

satela [25.4K]4 years ago

3 0

Answer:

80 Meters.

Explanation:

What I did was took how many seconds the ball traveled and multiply how fast the ball was going. I actually do a lot of these questions. :))

May I please have brainlyest??

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in 1984 don, disk that stayed aloft for 16.7 seonds supsuppose cain ran up a staricase during this time, reachig a height of 18.

laila [671]

Answer

given,

time of disk stayed a loft = 16.7 sec

height reached = 18.4 m

mass = 72 kg

now work done is equal to change in potential energy

$W = - (U_f - U_i)$

$W = - (mgh - 0)$

$W = - (72\times (-9.8) \times 18.4)$

W = 12983.04 J

Positive sign means that work is in the direction of motion.

$Power = \dfrac{Work\ done}{time}$

$Power = \dfrac{W}{t}$

$Power = \dfrac{12983.04}{16.7}$

P = 777.42 Watts

8 0

3 years ago

A stone falls from rest from the top of a cliff. A second stone is thrown downward from the same height 2.7 s later with an init

Darina [25.2K]

Answer:4.05 s

Explanation:

Given

First stone is drop from cliff and second stone is thrown with a speed of 52.92 m/s after 2.7 s

Both hit the ground at the same time

Let h be the height of cliff and it reaches after time t

$h=\frac{gt^2}{2}$

For second stone

$h=52.92\times \left ( t-2.7\right )+\frac{g\left ( t-2.7\right )^2}{2}$ ---2

Equating 1 &2 we get

$\frac{gt^2}{2}=52.92\times \left ( t-2.7\right )+\frac{g\left ( t-2.7\right )^2}{2}$

$\frac{g}{2}\left ( t-t+2.7\right )\left ( 2t-2.7\right )-\left ( t-2.7\right )52.92=0$

$13.23\times \left ( 2t-2.7\right )-\left ( t-2.7\right )52.92=0$

$26.46t-35.721-52.92t+142.884=0$

$t=4.05 s$

4 0

3 years ago

6.P.2.1 Matter: Properties and Changes Notes

Zinaida [17]

Answer:

The __law__ conservation

of state that either energy may produced nor destroyed

8 0

4 years ago

An incandescent bulb is supplied with

Serga [27]

Answer:

Efficiency = 5%

Explanation:

Given that,

Supplies energy to the bulb = 100 J

Transferred energy by the bulb = 5 J

We need to find the efficiency of the bulb. It can be given by "

$\eta=\dfrac{\text{useful energy out}}{\text{useful energy in}}\times 100\\\\=\dfrac{5}{100}\times 100\\\\=5\%$

So, the efficiency of the bulb is 5%.

8 0

3 years ago

Which formulas might be used to find the velocity based on a position-time graph?

Alex787 [66]

The formula to get the velocity is V=D/T. First you need to determine the distance and time at a certain point and plug it into the equation and that will be your velocity at that point. To get it between two points you complete the directions two times and find the average or use the slope formula, slope = rise/run; slope = (y2 - y1) / (x2 - x1).

6 0

4 years ago