Gina rolled a ball down a hill.

Physics

1 answer:

satela [25.4K]4 years ago

3 0

Answer:

80 Meters.

Explanation:

What I did was took how many seconds the ball traveled and multiply how fast the ball was going. I actually do a lot of these questions. :))

May I please have brainlyest??

You might be interested in

A ball is thrown upward at an angle with a speed and direction such that it reaches a maximum height of 16.0 m above the point i

shtirl [24]

To solve this problem it is necessary to apply the concepts related to the kinematic equations of motion for which the height of a particle is defined as a function of gravity as,

$v^2 = 2gh$

Where,

h = Height

g = Gravity constant

v = Velocity

There is not change in the horizontal component, therefore there is only the component horizontal given (18m/s) and the vertical component:

$v^2=2*g*h$

$v^2=2*9.8*16$

$v=17.70 m/s$

Applying the vector theory to find the magnitude of a vector we have to

$|\vec{V}| = \sqrt{17.7^2+18^2}$

$|\vec{V}| = 25.38m/s$

The speed at which the ball was thrown was 25.38

3 0

3 years ago

Electrons moving back and forth through a circuit would be

yaroslaw [1]

The particles that carry charge through wires in a circuit are mobile electrons. The electric field direction within a circuit is by definition the direction that positive test charges are pushed. Thus, these negatively charged electrons move in the direction opposite the electric field.

5 0

4 years ago

This is a velocity versus time graph of a car starting from rest. If the area under the line is 10 meters: what is the correspon

shtirl [24]

Answer: The correct answer is option (D).

Explanation:

The area under the line is 10 meters that is displacement which means that area enclosed by the right angled triangle is 10 unit squares.

So, the it can be written as:

$\text{area of triangle}=\frac{1}{2}\times velocity\times time$