Answer:
The radius r of the metal sphere.
Explanation:
From Gauss's law we know that for a spherical charge distribution with charge 
, the electrical field at distance 
from the center of the sphere is given by
What is important to notice here is that the radius of the sphere does not matter because any test charge sitting at distance feels the force as if all the charge were sitting at the center of the sphere.
This situation is analogous to the gravitational field. When calculating gravitational force due to a body like the sun or the earth, we take not of only the mass of the sun and the distance from it's center; the sun's radius does not matter because we assume all of its mass to be concentrated at the center.
Answer:
<em><u>♧</u></em><em><u> </u></em><em><u>Write</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>abbreviation</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>each</u></em><em><u> </u></em><em><u>metric</u></em><em><u> </u></em><em><u>unit</u></em><em><u>.</u></em>
- kg
- m
- g
- mL
- mm
- L
- km
- cm
- mg
<em><u>♧</u></em><em><u> </u></em><em><u>Try</u></em><em><u> </u></em><em><u>these</u></em><em><u> </u></em><em><u>conversions</u></em><em><u>,</u></em><em><u> </u></em><em><u>using</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>ladder</u></em><em><u> </u></em><em><u>method</u></em><em><u>.</u></em>
- 2 g
- 104000 m
- 4.8 m
- 5600 g
- 0.8 cm
- 5000 mL
- 0.198 kg
- 0.075 L
- 0.5 m
- 560 cm
- 160 mm
- 2.5 km
- 65000 mg
- 63 mm
- 0.12 g
<em><u>♧</u></em><em><u> </u></em><em><u>Compare</u></em><em><u> </u></em><em><u>using</u></em><em><u> </u></em><em><u><</u></em><em><u>,</u></em><em><u> </u></em><em><u>></u></em><em><u>,</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>=</u></em><em><u>.</u></em>
16. <
17. >
18. =
19. =
20. <
21. >
1.085m
Explanation:
Using
a= lambda/sinစ
Sinစ= (587.5*10^-9) x 0.75*10^-3
= 0.000783
Sinစ=0.875*10^-3/d
0.000783= 0.875/d
d= 1.085m
Answer:
The holiday lasted for 18 days.
Explanation:
Let's assume the number of days are as following:
let the rain in the morning and lovely afternoon = X days
Clear morning and rain in the afternoon = Y days
No rain in the morning and in the afternoon = Z days
Now according to the question
Number of days with rain = X + Y = 13 days
Number of days with clear mornings = Y + Z = 11 days
Number of days with clear afternoons = X + Z = 12 days
Solving above 3 equations, we get
X = 7, Y = 6 and Z = 5
Now total number of days on holiday = X+Y+Z = 7+6+5 =18
Hence, total number of days on holiday = 18 days.
We know from that other question that her mass is 60 kg, and
Weight = (mass) x (gravity)
Earth weight = (60 kg) x (9.8 m/s^2)
Weight = 588 Newtons
