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Mariulka [41]
3 years ago
10

HELP!!! The planet Mars has a mass about one-tenth the mass of Earth. Even though Mars has two moons, their tidal forces have a

much weaker effect on Mars than Earth’s moon does on Earth. Why do you think this is? Use the data in the tables to support your prediction.

Physics
1 answer:
vladimir2022 [97]3 years ago
4 0

Answer:

Say: Mars has a much weaker gravity effect than it does because it is smaller and cannot have as much gravity effect than it does on earth.

Explanation:

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Answer:

what is the hunting age? i've never heard of it

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How and where is old oceanic crust destroyed?
sladkih [1.3K]

Answer:

It is destroyed in subduction zones. A Geologic process in which a tectonic plate made of dense lithospheric material melts or falls below a plate made of less-dense lithosphere at a convergent plate boundary

Explanation:

Hope this helps (:

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3 years ago
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While performing an experiment, the student creating the data table is not sure if a measurement from the experiment is a vector
marin [14]

Before coming into conclusion first we have to understand both scalar and vector .

A scalar quantity is a physical quantity which has only magnitude for it's complete specification.

A vector quantity is that physical quantity which not only requires magnitude but also possesses direction for it's complete specification.

So the most important factor that differentiate vector from scalar is the direction.

As per the question the student is doing an experiment where he is recording the data obtained during the process.

In order to arrange them in data table, he should ask about the direction of the quantity under consideration.


Hence the correct option is the third option(C)i.e does the measurement include direction?




7 0
3 years ago
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The aurora is caused when electrons and protons, moving in the earth’s magnetic field of ≈5.0×10−5T, collide with molecules of t
ollegr [7]

Answer:

8.79*10^6 rad/s

Explanation:

To find the frequency of the circular orbit for an electron you use the following expression, for the radius of the trajectory of an electron, that travels trough a constant magnetic field:

r=\frac{mv}{qB}         (1)

r: radius of the trajectory

m: mass of the electron = 9.1*10^-31 kg

v: speed of the electron = 1.0*10^6 m/s

q: charge of the electron = 1.6*10^-19 C

B: magnitude of the magnetic field = 5.0*10^-5 T

You use the fact that the angular frequency in a circular motion is given by:

\omega=\frac{v}{r}

Then, you solve the equation (1) in order to obtain v/r:

\frac{v}{r}=\omega=\frac{qB}{m}

Finally, you replace the values of the parameters:

\omega=\frac{(1.6*10^{-19}C)(5.0*10^{-5}T)}{9.1*10^{-31}kg}\\\\\omega=8.79*10^6\frac{rad}{s}

hence, the angular frequency is 8.79*10^6 rad/s

The frequency is:

f=2\pi \omega=5.5*10^7Hz

5 0
3 years ago
KE=0.5.m.v2 or PE=m.g.h
LUCKY_DIMON [66]

Answer:

1. 37.8J

2. 18 Billion Joules, 18 Gigajoules

3. 9.81 Billion Joules, 9.81 Gigajoules

Explanation:

Use the formulas provided,

KE=(1/2)mv^2 and PE=mgh, noting that g=9.81

7 0
2 years ago
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