Ask question

Ask question

All categories

2 years ago

10

HELP!!! The planet Mars has a mass about one-tenth the mass of Earth. Even though Mars has two moons, their tidal forces have a

much weaker effect on Mars than Earth’s moon does on Earth. Why do you think this is? Use the data in the tables to support your prediction.

1 answer:

vladimir2022 [97]2 years ago

4 0

Answer:

Say: Mars has a much weaker gravity effect than it does because it is smaller and cannot have as much gravity effect than it does on earth.

Explanation:

You might be interested in

WILL GIVE BRAINLIEST!

Bad White [126]

Answer:

A. Deposition

B. Condensation

C. Freezing

Explanation:

We have three changes of state shown in the picture:

- Deposition: it is the change of state of a substance from gas to solid state, without going through the liquid phase. In this process, energy is released, as the average energy of the molecules of the substance decrease, releasing it to the surroundings.

- Condensation: it is the change of state of a substance from gas to liquid state. In this process, energy is also released, as the average energy of the molecules of the substance decrease as the substance becomes a liquid, releasing it to the surroundings.

- Freezing: it is the change of state of a substance from liquid to solid state. In this process, energy is also released, as the average energy of the molecules of the substance decrease as the substance becomes a solid, releasing it to the surroundings.

3 0

3 years ago

Read 2 more answers

Mechanics is the study of

svetoff [14.1K]

Mechanics is the study of motion and force on physical objects and their surroundings

4 0

3 years ago

Find the distance between two slits that produces the first minimum for 410-nm violet light at an angle of 45.0°

Tpy6a [65]

Answer:

Distance between slits, $d=2.89\times 10^{-7}\ m$

Explanation:

It is given that,

Wavelength, $\lambda=410\ nm=410\times 10^{-9}\ m$

Angle, $\theta=45$

We need to find the distance between two slits that produces first minimum. The equation for the destructive interference is given by :

$d\ sin\theta=(n+\dfrac{1}{2})\lambda$

For first minimum, n = 0

So, $d\ sin\theta=(\dfrac{1}{2})\lambda$

d is the distance between slits

So, $d=\dfrac{1/2\lambda}{sin\theta}$

$d=\dfrac{1/2\times 410\times 10^{-9}}{sin(45)}$

$d=2.89\times 10^{-7}\ m$

So, the distance between two slits is $2.89\times 10^{-7}\ m$ . Hence, this is the required solution.

6 0

3 years ago

A fixed coil of wire with 10 turns and an area of 0.055 m2 is placed in a perpendicular magnetic field. This field oscillates in

Blababa [14]

Answer:

Part a)

Average EMF for half cycle is

$E_{avg} = 2.64 V$

Part b)

For one complete cycle we will have

$E_{avg} = 0$

Part c)

Maximum induced EMF will be at

t = 0.025 s and 0.075 s

minimum induced EMF is at

t = 0.05s and 0.1 s

Explanation:

As we know that magnetic field is oscillating in direction as well as magnitude

so induced EMF is given as

$E = NBA\omega sin(\omega t)$

Part a)

For average value of EMF from positive maximum to negative maximum which is equal to half cycle

so we have

$E_{avg} = NBA\omega \frac{2}{T}\int_0^{T/2} sin(\omega t) dt$

$E_{avg} = \frac{2NBA\omega}{\pi}$

$E_{avg} = \frac{2(10)(0.12)(0.055)(2\pi (10))}{\pi}$

$E_{avg} = 2.64 V$

Part b)

For one complete cycle we will have

$E_{avg} = NBA\omega \frac{1}{T}\int_0^T sin(\omega t) dt$

$E_{avg} = 0$

Part c)

Maximum induced EMF will be at

$t = \frac{T}{4} and \frac{3T}{4}$

here we know

$T = \frac{1}{f} = 0.1 s$

t = 0.025 s and 0.075 s

minimum induced EMF is at

$t = \frac{T}{2} and T$

so it is

t = 0.05s and 0.1 s

8 0

3 years ago

the car starts from rest at s=0 and increases its speed at at=4m/s^2. Determine the time when the magnitude of acceleration beco

dem82 [27]

Answer:

<em>Time = 5 seconds</em>

<em>Distance = 50 meters</em>

Explanation:

<u>Constantly Accelerated Motion</u>

When the velocity of a moving object changes at a constant rate, called acceleration, the velocity changes in same amounts in the same times. The question has a mistake when asking when the acceleration is 20 m/s. If the acceleration is constant, the only variable that can change to that value is the velocity. The equation to calculate the speed is

$v_f=v_o+a.t$

And the distance s is

$\displaystyle s=v_o.t+\frac{gt^2}{2}$

Given the object starts from rest, vo=0 and vf=20 m/s at $a=4\ m/s^2$ . We compute t

$\displaystyle t=\frac{v_f-v_o}{a}=\frac{20-0}{4}$

$\boxed{t=5\ sec}$

Now we compute s

$\displaystyle s=0+\frac{4\times 5^2}{2}$

$\boxed{s=50\ m}$

5 0

2 years ago