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3 years ago

14

A superconductor performs best at ______.

1 answer:

vlada-n [284]3 years ago

3 0

Answer:

c

Explanation:

Superconductors perform best at very cold temperatures because resistivity of this kind of materials decays drastically with temperature. Chromium is most likely to be the best conductor of electricity because it belongs to the Transition Metal group of the periodic table

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A 4 kg object is moving at a speed of 5 m/sec. How much kinetic energy does the object have? A. 10 joules B. 20 joules C. 50 jou

sp2606 [1]

Answer:

A. 10 joules

Explanation:

Given parameters:

Mass of object = 4kg

Speed = 5m/s

Unknown:

Kinetic energy of the the object = ?

Solution:

Kinetic energy is the energy due to a moving body.

So;

mathematically;

K.E = $\frac{1}{2}$ x m v²

m is the mass

v is the velocity

K.E = $\frac{1}{2}$ x 4 x 5 = 10J

5 0

3 years ago

Elmotordeuncarroda2000revolucionesporminuto<br><br> .Calcularsuperíodoysufrecuencia.

Andrew [12]

can u translate pls

Explanation:

5 0

3 years ago

Match each situation below to a letter on the illustration.

kari74 [83]

Answer:

What illustration

Explanation:

7 0

3 years ago

Solenoid 2 has twice the diameter, twice the length, and twice as many turns as solenoid 1. How does the field B2 at the center

klemol [59]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is option 3

Explanation:

From the question we are told that

The diameter of solenoid 1 is $d_1$

The length of solenoid 1 is $L_1$

The number of turns of solenoid is $N_1$

The diameter of solenoid 2 is $d_2 = 2d_1$

The length of solenoid 2 is $L_2 = 2L_1$

The number of turns of solenoid 2 is $N_2 = 2 N_1$

Generally the magnetic in a solenoid is mathematically represented as

$B = \frac{\mu_o * N * I }{L}$

From this equation we see that

$B \ \alpha \ \frac{N}{L}$

$B = C \frac{N}{L}$

Here C stands for constant

=> $C = \frac{B * \frac{L}{N}$

=> $\frac{B_1 * \frac{L_1}{N_1} = \frac{B_2 * \frac{L_2}{N_2}$

=> $\frac{B_1}{B_2 } = \frac{N_1 L _2}{ N_2L_1}$

=> $\frac{B_1}{B_2 } = \frac{N_1 * (2 L_1)}{ (2 N_2)L_1}$

=> $\frac{B_1}{B_2 } = 1$

=> $B_2 = B_1$

4 0

4 years ago

An iron anchor of density 7890.00 kg/m3 appears 299 N lighter in water than in air. (a) What is the volume of the anchor? (b) Ho

PtichkaEL [24]

Answer:

weigh is 2353.13 N

Explanation:

Given data

density = 7890.00 kg/m3

lighter = 299 N

to find out

the volume of the anchor and weigh in air

solution

from question we can say that

apparent weight = actual weight - buoyant force

we know weight = mg and buoyant force = water density × g

so volume of anchor is = actual weight - apparent weight / buoyant force

volume of anchor is = 299 / 1000 × 9.81

volume of anchor is = 0.0304791 m³

and

weight of anchor is mg

here mass m = density Fe g

density Fe = 7870 from table 14-1

so weight = 7870 × 0.0304791 × 9.81

weigh is 2353.13 N

7 0

4 years ago