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denis23 [38]
2 years ago
6

Hello Can anyone help me. ​

Physics
1 answer:
labwork [276]2 years ago
3 0

(G)-->Iron and steel industry is called a heavy industry because all the raw material as well as finished goods are heavy and bulky entailing heavy transportation costs. Iron ore, coking coal and limestone are required in the ratio of 4:2:1 approximately. Some quantity of manganese is also required to harden the steel.

(H)-->Sodium is very reactive in nature. When exposed in air, it automatically forms Na2O. When it is put in water it reacts vigorously and starts burning on water. Due to the above reasons Sodium is called an active metal.

(I)-->Down the group, the effective nuclear charge experienced by valence electrons is decreasing because the outermost electrons are far away from the nucleus. Thus, these electrons can be lost easily by the element to form positive ions. Hence, the chemical reactivity of metals increases on going down a group.

(J)-->While moving from top to bottom in a group of the periodic table, the reactivity of non- metals decreases. While moving from top to bottom in a group of non- metals, the atomic size increases with the additional number of shells and the force of attraction between the nucleus and valence shell decreases.

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Mechanical waves propagate or move through a medium because
lys-0071 [83]
The answer to that would be that 

they require so its mandatory for mechanical waves to travel through a medium
8 0
3 years ago
Where c is a constant that depends on the initial gas pressure behind the projectile. The initial position of the projectile is
Ronch [10]

Complete Question

A gas gun uses high pressure gas tp accelerate projectile through the gun barrel.

If the acceleration of the projective is : a = c/s m/s​2

Where c is a constant that depends on the initial gas pressure behind the projectile. The initial position of the projectile is s= 1.5m and the projectile is initially at rest. The projectile accelerates until it reaches the end of the barrel at s=3m. What is the value of the constant c such that the projectile leaves the barrel with velocity of 200m/s?

Answer:

The value of the constant is  c = 28853.78 \ m^2 /s^2

Explanation:

From the question we are told that

         The acceleration is  a =  \frac{c}{s}\   m/s^2

         The  initial position of the projectile is s= 1.5m

         The final position of the projectile is s_f =  3 \ m

          The velocity is  v = 200 \ m/s

     Generally  time  =  \frac{ds}{dv}

   and  acceleration is a =  \frac{v}{time }

so

            a = v  \frac{dv}{ds}

 =>        vdv  =  a ds

             vdv  = \frac{c}{s}  ds

integrating both sides

           \int\limits^a_b  vdv  = \int\limits^c_d \frac{c}{s}  ds

Now for the limit

          a =  200 m/s

             b = 0 m/s  

         c = s= 3 m

          d =s_f= 1.5 m

So we have  

           \int\limits^{200}_{0}  vdv  = \int\limits^{3}_{1.5} \frac{c}{s}  ds

              [\frac{v^2}{2} ] \left | 200} \atop {0}} \right.  = c [ln s]\left | 3} \atop {1.5}} \right.

            \frac{200^2}{2}  =  c ln[\frac{3}{1.5} ]

=>           c = \frac{20000}{0.69315}

              c = 28853.78 \ m^2 /s^2

     

5 0
3 years ago
In the Compton effect, the wavelength of the scattered photon is __________ the wavelength of the incident photon.
SOVA2 [1]

Answer:

he wavelength is different (greater) than the wavelength of the incident photon

Explanation:

The Compton effect is the scattering of a photon by an electron, this process is analyzed using the conservation of momentum, in which we assume that initially the electron is at rest and after the collision it recedes, therefore the energy of the incident photon decreases and consequently its wavelength changes

To complete the sentence we use the wavelength is different (greater) than the wavelength of the incident photon

3 0
3 years ago
during a typical afternoon thunderstorm in the summer, an area of 66.0 km2 receives 9.57 108 gal of rain in 18 min. how many inc
zheka24 [161]

Answer:

2.16 inch

Explanation:

area under water = 66 km²

= 66 x ( 3280.84 x 12 )² inch²

= 1.023 x 10¹¹ sq inch

volume of rain = 9.57 x 10⁸  gallon = 9.57 x 10⁸ x 231 inch³

= 2.21 x 10¹¹ inch³

If depth of rainfall be t

volume of rain = surface area x depth

= 1.023 x 10¹¹ x t

So ,

1.023 x 10¹¹ x t  = 2.21 x 10¹¹

t = 2.16 inch

5 0
2 years ago
Large wind turbines with a power capacity of 8 MW and blade span diameters of over 160 m are available for electric power genera
IrinaK [193]

Answer:

The electric power generated by the wind turbine is 1105.84 kWh

The amount of electric energy generated is 26540.17 kWh

The revenue generated per day is $2388.62

Explanation:

Consider a wind turbine with a blade

Span diameter of 100 m installed at a site

subjected to steady winds at 8 m/s

l.e wind speed v = 8 m/s

Span diameter d = 100 m

A, sweap area = πd² / 4

                        = π x 100² / 4

                        = 7853.98 m²

Lets solve for wind speed v = 8 m/s

Density of Area ρ = 1.25 kg/m³

η = 44%

P = 1/2 ρAv³η

  = 1/2 x 1.25 x 785.98 x 8³ x 44/100

  = 1/2 x 1.25 x 7853.98 x 512 x 0.44

  = 1105840.38

  = 1.10584038 mw

  = 1105.84038 kWh

  = 1105.84 kWh

Energy generated by wind turbine per day

⇒ P x H

      = 1105.84038 x 24

      = 26540.16912 kwh

      = 26540.17 kwh      

Revenue generated per day = Energy x 0.09 kwh

                                                = 26540.16912 x 0.09

                                                = $2388.615

                                                = $2388.62

4 0
3 years ago
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