Answer:
n = 10 beats
Explanation:
Given:
- Frequency of note f1 = 151 Hz
- Frequency of note f2 = 155 Hz
- The total time they ring t = 2.5 s
Find:
How many beats are heard
Solution:
- The frequency of beat (fb) is the difference between the two frequencies of notes as follows:
fb = f2 - f1
fb = 155 - 151
fb = 4 Hz
- The number of beats per second is also called beat frequency:
n = fb*t
n = 4*2.5
n = 10 beats
Are you joking? Why is this on here?
when we placed in the container of real depth assuming = d
if the container filled with liquid A then its apparent depth d' = 7cm
so the refractive index nA = real depth / apparent depth
= d/7cm = 0.1428d
if the container filled with liquid B then its apparent depth d' = 6cm
so the refractive index nB = real depth / apparent depth
= d/6cm = 0.166d
if the container filled with liquid C then its apparent depth d' = 5cm
so the refractive index nC = real depth / apparent depth
= d/5cm = 0.2d
Since the refractive index is inversely proportional to the apparent depth
then the refractive indices are nC > nB > nA
Answer:
Explanation:
F = ma
<u>Assuming</u> the 20° is angle θ measured to the horizontal
mgsinθ - μmgcosθ = ma
g(sinθ - μcosθ) = a
at constant velocity, a = 0
g(sinθ - μcosθ) = 0
sinθ - μcosθ = 0
sinθ = μcosθ
μ = sinθ/cosθ
μ = tanθ
μ = tan20
μ = 0.3639702342...
μ = 0.36