The answer to that would be that
they require so its mandatory for mechanical waves to travel through a medium
Complete Question
A gas gun uses high pressure gas tp accelerate projectile through the gun barrel.
If the acceleration of the projective is : a = c/s m/s2
Where c is a constant that depends on the initial gas pressure behind the projectile. The initial position of the projectile is s= 1.5m and the projectile is initially at rest. The projectile accelerates until it reaches the end of the barrel at s=3m. What is the value of the constant c such that the projectile leaves the barrel with velocity of 200m/s?
Answer:
The value of the constant is 
Explanation:
From the question we are told that
The acceleration is 
The initial position of the projectile is s= 1.5m
The final position of the projectile is 
The velocity is 
Generally 
and acceleration is 
so

=> 

integrating both sides

Now for the limit
a = 200 m/s
b = 0 m/s
c = s= 3 m
d =
= 1.5 m
So we have

![[\frac{v^2}{2} ] \left | 200} \atop {0}} \right. = c [ln s]\left | 3} \atop {1.5}} \right.](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bv%5E2%7D%7B2%7D%20%5D%20%5Cleft%20%7C%20200%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.%20%20%3D%20c%20%5Bln%20s%5D%5Cleft%20%7C%203%7D%20%5Catop%20%7B1.5%7D%7D%20%5Cright.)
![\frac{200^2}{2} = c ln[\frac{3}{1.5} ]](https://tex.z-dn.net/?f=%5Cfrac%7B200%5E2%7D%7B2%7D%20%20%3D%20%20c%20ln%5B%5Cfrac%7B3%7D%7B1.5%7D%20%5D)
=> 

Answer:
he wavelength is different (greater) than the wavelength of the incident photon
Explanation:
The Compton effect is the scattering of a photon by an electron, this process is analyzed using the conservation of momentum, in which we assume that initially the electron is at rest and after the collision it recedes, therefore the energy of the incident photon decreases and consequently its wavelength changes
To complete the sentence we use the wavelength is different (greater) than the wavelength of the incident photon
Answer:
2.16 inch
Explanation:
area under water = 66 km²
= 66 x ( 3280.84 x 12 )² inch²
= 1.023 x 10¹¹ sq inch
volume of rain = 9.57 x 10⁸ gallon = 9.57 x 10⁸ x 231 inch³
= 2.21 x 10¹¹ inch³
If depth of rainfall be t
volume of rain = surface area x depth
= 1.023 x 10¹¹ x t
So ,
1.023 x 10¹¹ x t = 2.21 x 10¹¹
t = 2.16 inch
Answer:
The electric power generated by the wind turbine is 1105.84 kWh
The amount of electric energy generated is 26540.17 kWh
The revenue generated per day is $2388.62
Explanation:
Consider a wind turbine with a blade
Span diameter of 100 m installed at a site
subjected to steady winds at 8 m/s
l.e wind speed v = 8 m/s
Span diameter d = 100 m
A, sweap area = πd² / 4
= π x 100² / 4
= 7853.98 m²
Lets solve for wind speed v = 8 m/s
Density of Area ρ = 1.25 kg/m³
η = 44%
P = 1/2 ρAv³η
= 1/2 x 1.25 x 785.98 x 8³ x 44/100
= 1/2 x 1.25 x 7853.98 x 512 x 0.44
= 1105840.38
= 1.10584038 mw
= 1105.84038 kWh
= 1105.84 kWh
Energy generated by wind turbine per day
⇒ P x H
= 1105.84038 x 24
= 26540.16912 kwh
= 26540.17 kwh
Revenue generated per day = Energy x 0.09 kwh
= 26540.16912 x 0.09
= $2388.615
= $2388.62