Answer:
F=1.4384×10⁻¹⁹N
Explanation:
Given Data
Charge q= -8.00×10⁻¹⁷C
Distance r=2.00 cm=0.02 m
To find
Electrostatic force
Solution
The electrostatic force between between them can be calculated from Coulombs law as
![F=\frac{kq^{2} }{r^{2} }](https://tex.z-dn.net/?f=F%3D%5Cfrac%7Bkq%5E%7B2%7D%20%7D%7Br%5E%7B2%7D%20%7D)
Substitute the given values we get
![F=\frac{(8.99*10^{9} )*(-8.00*10^{-17} )^{2} }{(0.02)^{2} }\\ F=1.4384*10^{-19} N](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B%288.99%2A10%5E%7B9%7D%20%29%2A%28-8.00%2A10%5E%7B-17%7D%20%29%5E%7B2%7D%20%7D%7B%280.02%29%5E%7B2%7D%20%7D%5C%5C%20F%3D1.4384%2A10%5E%7B-19%7D%20N)
Vi=12m/s Vf=16m/s t=8s a=? a=Vf-Vi/t=16-12/8=4/8=1/2 a=0.5m/s^2
<em>I'm sorry, it says check all that apply, however there are no choices given. You should edit, and add the multiple choice answers.</em>
My Answer:
Well if the masses of two objects were both decreased, it would result in a decrease in the gravitational force. So I guess the two objects masses would need to be decreased.
Answer:
The pressure exerted by camel feet is <u>2000 N/m²</u>.
Step-by-step explanation:
<h3><u>Solution</u> :</h3>
Here, we have given that ;
- Force applied on camel feet = 4000 N
- Total area of camel feet = 2 m²
We need to find the pressure exerted by camel feet.
As we know that :
![{\longrightarrow{\pmb{\sf{Pressure= \dfrac{Area}{Force}}}}}](https://tex.z-dn.net/?f=%7B%5Clongrightarrow%7B%5Cpmb%7B%5Csf%7BPressure%3D%20%5Cdfrac%7BArea%7D%7BForce%7D%7D%7D%7D%7D)
Substituting all the given values in the formula to find the pressure exerted by camel feet.
![\begin{gathered} \begin{array}{l} {\longrightarrow{\sf{Pressure= \dfrac{Area}{Force}}}} \\ \\ {\longrightarrow{\sf{Pressure= \dfrac{4000}{2}}}} \\ \\ {\longrightarrow{\sf{Pressure= \cancel{\dfrac{4000}{2}}}}} \\ \\ {\longrightarrow{\sf{Pressure= 2000 \: N/{m}^{2}}}} \\ \\\star \: \small\underline{\boxed{\sf{\purple{Pressure= 2000 \: N/{m}^{2}}}}} \end{array}\end{gathered}](https://tex.z-dn.net/?f=%20%5Cbegin%7Bgathered%7D%20%5Cbegin%7Barray%7D%7Bl%7D%20%7B%5Clongrightarrow%7B%5Csf%7BPressure%3D%20%5Cdfrac%7BArea%7D%7BForce%7D%7D%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%5Clongrightarrow%7B%5Csf%7BPressure%3D%20%5Cdfrac%7B4000%7D%7B2%7D%7D%7D%7D%20%20%5C%5C%20%20%5C%5C%20%7B%5Clongrightarrow%7B%5Csf%7BPressure%3D%20%5Ccancel%7B%5Cdfrac%7B4000%7D%7B2%7D%7D%7D%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%5Clongrightarrow%7B%5Csf%7BPressure%3D%202000%20%5C%3A%20N%2F%7Bm%7D%5E%7B2%7D%7D%7D%7D%20%5C%5C%20%20%5C%5C%5Cstar%20%5C%3A%20%20%5Csmall%5Cunderline%7B%5Cboxed%7B%5Csf%7B%5Cpurple%7BPressure%3D%202000%20%5C%3A%20N%2F%7Bm%7D%5E%7B2%7D%7D%7D%7D%7D%20%5Cend%7Barray%7D%5Cend%7Bgathered%7D)
Hence, the pressure exerted by camel feet is 2000 N/m².
![\rule{300}{2.5}](https://tex.z-dn.net/?f=%5Crule%7B300%7D%7B2.5%7D)
Answer:
Negatively charged, to positively charged parts
Explanation:
Electrons are negative, negative is attracted to positive.