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3 years ago

Technician A says that TSBs are typically updates to the owner's manual. Technician B says that TSBs are generally

Engineering

1 answer:

vichka [17]3 years ago

4 0

Answer:

Technician A says that TSBs are typically updates to the owner's manual. Technician B says that TSBs are generally

updated information on model changes that do not affect the technician. Who is correct? the answer is c

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The output S/N at thereceiver must be greater than 40 dB. The audio signal has zero mean, maximum amplitude of 1, power of ½ Wan

abruzzese [7]

Given that,

The output signal at the receiver must be greater than 40 dB.

Maximum amplitude = 1

Bandwidth = 15 kHz

The power spectral density of white noise is

$\dfrac{N}{2}=10^{-10}\ W/Hz$

Power loss in channel= 50 dB

Suppose, Using DSB modulation

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Put the value into the formula

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Figure of merit = 1

We need to calculate the input signal

Using formula of FOM

$FOM=\dfrac{\dfrac{S_{o}}{N_{o}}}{\dfrac{S_{i}}{N_{i}}}$

$1=\dfrac{\dfrac{S_{o}}{N_{o}}}{\dfrac{S_{i}}{N_{i}}}$

$\dfrac{S_{i}}{N_{i}W}=\dfrac{S_{o}}{N_{o}}$

Put the value into the formula

$\dfrac{S_{i}}{2\times10^{-10}\times15\times10^{3}}$

$\dfrac{S_{i}}{30\times10^{-7}}$

$S_{i}$

$S_{i}=30\times10^{-3}$

We need to calculate the transmit power

Using formula of power transmit

$S_{i}=\dfrac{P_{t}}{P_{L}}$

$P_{t}=S_{i}\times P_{L}$

Put the value into the formula

$P_{t}=30\times10^{-3}\times10^{5}$

$P_{t}=3\ kW$

We need to calculate the needed bandwidth

Using formula of bandwidth for DSB modulation

$bandwidth=2W$

Put the value into the formula

$bandwidth =2\times15$

$bandwidth = 30\ kHz$

Hence, The transmit power is 3 kW.

The needed bandwidth is 30 kHz.

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