Answer:
<em>55%</em>
Explanation:
hot reservoir = 1100 K
cold reservoir = 500 K
<em>This is a Carnot system</em>
For a Carnot system, maximum efficicency of the system is given as
Eff = 1 - 
where Tc = temperature of cold reservoir = 500K
Th = temperature of hot reservoir = 1100 K
Eff = 1 - 
Eff = 1 - 0.45 = 0.55 or<em> 55%</em>
I need more details to your question
Explanation:
Given T = 10 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (10 + 273.15) K = 283.15 K
<u>T = 283.15 K </u>
The conversion of T( °C) to T(F) is shown below:
T (°F) = (T (°C) × 9/5) + 32
So,
T (°F) = (10 × 9/5) + 32 = 50 °F
<u>T = 50 °F</u>
The conversion of T( °C) to T(R) is shown below:
T (R) = (T (°C) × 9/5) + 491.67
So,
T (R) = (10 × 9/5) + 491.67 = 509.67 R
<u>T = 509.67 R</u>
convert 40db to standard gain
AL=10^40/20=100
calculate total voltage gain
=AL×RL/RL+Ri
=83.33
38.41 DB
calculate power
Pi=Vi^2/Ri Po=Vo^2/RL
power gain= Po/Pi
=13.90×10^6
