The statements which are true about client-side DNS include all of the following;
B. Client-side DNS should be configured to point towards the DNS server that is authoritative for the domain that client wants to join.
C. Check out DNS settings using the NSLookup command.
D. Check out DNS settings using the DIG command.
E. The cache.dns file has the IP addresses of the 13 root DNS servers.
B. If a web site can be reached by IP address and not by host name, then DNS or the Hosts file would be the problem.
<h3>What is a DNS server?</h3>
In Computer technology, a DNS server can be defined as a type of server that is designed and developed to translate domain names into IP addresses, so as to allow end users access websites and other internet resources through a web browser.
This ultimately implies that, a DNS server simply refers to a type of server that is designed and developed to translate requests for domain names into IP addresses for end users.
Read more on a domain names here: brainly.com/question/19268299
#SPJ1
What are the answer choices?
Without the choices, I’d say so that they can further progress their engineering education. New technologies and new mechanical advancements are always coming out so it would be beneficial for the engineer to keep up to date by taking classes.
The answer to this problem is the results of the point A
Answer:
The algorithm is as follows:
1. Declare Arr1 and Arr2
2. Get Input for Arr1 and Arr2
3. Initialize count to 0
4. For i in Arr2
4.1 For j in Arr1:
4.1.1 If i > j Then
4.1.1.1 count = count + 1
4.2 End j loop
4.3 Print count
4.4 count = 0
4.5 End i loop
5. End
Explanation:
This declares both arrays
1. Declare Arr1 and Arr2
This gets input for both arrays
2. Get Input for Arr1 and Arr2
This initializes count to 0
3. Initialize count to 0
This iterates through Arr2
4. For i in Arr2
This iterates through Arr1 (An inner loop)
4.1 For j in Arr1:
This checks if current element is greater than current element in Arr1
4.1.1 If i > j Then
If yes, count is incremented by 1
4.1.1.1 count = count + 1
This ends the inner loop
4.2 End j loop
Print count and set count to 0
<em>4.3 Print count</em>
<em>4.4 count = 0</em>
End the outer loop
4.5 End i loop
End the algorithm
5. End