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anzhelika [568]
3 years ago
10

Teaching how to characterize and implement high speed power devices for tomorrow's engineers

Engineering
1 answer:
Simora [160]3 years ago
6 0

Answer: Teaching how to characterize and implement high speed power devices for tomorrow's engineers

Explanation:

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krek1111 [17]

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ANSI A sized paper is commonly referred to as Letter and ANSI B as Ledger or Tabloid.

Explanation:

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public interface Frac { /** @return the denominator of this fraction */ int getDenom(); /** @return the numerator of this fracti
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The Full details of the answer is attached.

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(Almost) FREE POINTS!!!!! Hey there, Im writting a research paper, and I want to know if you think NASA is a waste of money or n
tatuchka [14]

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Explanation:

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3 years ago
Read 2 more answers
Using the AASHTO procedure, determine the thickness required for a base and a surface layer over existing subgrade. The structur
garri49 [273]

Answer:

<u>the thickness required would be 12 inch HMA and granular base layer of 6 inches</u>

Explanation:

structural number = 4.5

stone base course material coefficient = 0.13

hma material layer coefficient = 0.40

drainage coefficient = 0.90

we will use layered analysis procedure to get thickness

D1 >= sN1/a1

when we cross multiply,

sN1 = a1D1 >=sN1

D2 >= -sN2-sN1/a2m2

sN2* + sN1* >= sN2

D3 >= sN3-(sN1*+sN2*)/a2m2

where a1,a2,a3 = layer coefficient

d1 d2 d3 = actual thickness

m2,m3 = coefficient of base

a1 = 0.4

a1 = 0.13

sN = 4.5

m2 = 0.9

D1 >= sN1/a1 = 4.5/0.4

= 11.25

thickness of surface = 12 inches

a1D1 = 0.4x12 = 4.8

we have value of sN2 = 5.5

(5.5 -4.8)/(0.13*0.9)

= 0.7/0.117

= 5.9829 inches

approximately 6 inches

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7 0
3 years ago
In Java; Given numRows and numColumns, print a list of all seats in a theater. Rows are numbered, columns lettered, as in 1A or
baherus [9]

Answer:

Explanation:

import java.util.Scanner;

public class NestedLoops {

   public static void main (String [] args) {

       Scanner scnr = new Scanner(System.in);

       int numRows;

       int numColumns;

       int currentRow;

       int currentColumn;

       char currentColumnLetter;

       numRows = scnr.nextInt();

       numColumns = scnr.nextInt();

       for (currentRow = 0; currentRow < numRows; currentRow++) {

           currentColumnLetter = 'A';

           for (currentColumn = 0; currentColumn < numColumns; currentColumn++) {

               System.out.print(currentRow + 1);

               System.out.print(currentColumnLetter + " ");

               currentColumnLetter++;

           }

       }

       System.out.println("");

   }

}

2

3

1A  1B  1C  2A  2B  2C

thanks

5 0
3 years ago
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