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anzhelika [568]
3 years ago
10

Teaching how to characterize and implement high speed power devices for tomorrow's engineers

Engineering
1 answer:
Simora [160]3 years ago
6 0

Answer: Teaching how to characterize and implement high speed power devices for tomorrow's engineers

Explanation:

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The "Crawler" developed to transport the Saturn V launch vehicle from the assembly building to the launch pad is the largest lan
Illusion [34]

Answer:

a) 152000 slugs

b) 2220000 kg or 2220 metric tons

Explanation:

A body with a weight of 4.9*10^6 lbf has a mass of

4.9*10^6 lbm * 1 lbf/lbm = 4.9*10^6 lbm

This mass value can then be converted to other mass values.

1 slug is 32.17 lbm

Therefore:

4.9*10^6 lbm * 1 slug / (32.17 lbm) = 152000 slugs

1 lb is 0.453 kg

Therefore:

4.9*10^6 lbm / (1/0.453) * kg/lbm = 2220000 kg

5 0
4 years ago
A manufacturing company has decided to be carbon free by 2030.
k0ka [10]

Answer:

company should focus on their goals

4 0
3 years ago
The torque required to drive a 40 mm diameter power screw having double square threads with a pitch of 6 mm is 1.0 kN-m. The fri
myrzilka [38]

Answer:

This is self locking.

Explanation:

Given that

Diameter d= 40 mm

Pitch (P)= 6 mm

Torque T= 1 KN.m

Friction(μ) = 0.1

Thread is double square.

Condition for self locking

\mu >tan\theta

tan\theta=\dfrac{L} {\pi d}

L= n x P

N= number of start

Here given that double start so n=2

L=2 x 6 = 12 mm

tan\theta=\dfrac{L} {\pi d}

tan\theta=\dfrac{12} {\pi \times 40}

tan\theta=0.095            (μ = 0.1)

\mu >tan\theta

So from we can that this is self locking.

6 0
3 years ago
A company, which makes forging die wants to improve their steel parts and they contacted you because they heard you know a techn
ruslelena [56]

Answer:

a

Hardness Test

b

The available hardness test are

  • Rockwell hardness test
  • Vicker's hardness test
  • knoop test
  • scratch test
  • Brinell hardness test e.t.c

I would suggest Rockwell test because

  • It has good accuracy
  • In this test loads can be applied in 2 stages hence better results are obtained
  • it saves time because it testing are faster

c

   Well the following would be the reasons for low hardness value

  • It could be because the steel used has a low percentage of carbon
  • it could also result from the quenching medium used (e.g water , brine solution e.t.c)

d

In order to solve this problem here are the following ways

  • When selecting steel the ones with a carbon percentage 0.3% to 0.8% should be selected
  • When quenching the quenching medium should be brine solution  

Explanation:

The reason why the answer to question is hardness test is because the heat treatment was carried out to obtain hardness so if it is great then the heat treatment is good

7 0
4 years ago
E = 50V, R= 1000 ohms, then I =
Margarita [4]

Explanation:

<em>Current</em><em> </em><em>(</em><em>I)</em><em>=</em><em> </em><em><u>Voltage</u></em><em><u> </u></em><em><u>(</u></em><em><u>V)</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Resistance </em><em>(Ω)</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em>I=</em><em> </em><em><u>5</u></em><em><u>0</u></em><em><u>V</u></em>

<em> </em><em> </em><em> </em><em> </em><em>1000</em><em>(Ω)</em>

<em>I=</em><em> </em><em><u>5</u></em><em><u>V</u></em>

<em> </em><em> </em><em> </em><em> </em><em>1</em><em>0</em><em>0</em><em>(Ω)</em>

<em>I=</em><em> </em><em>0</em><em>.</em><em>0</em><em>5</em><em> </em><em>(</em><em>Amp)</em><em>. </em><em>Answer</em>

<em>Voltage=</em><em>V</em>

<em>Current</em><em>=</em><em>I</em>

<em>Resistance</em><em>=</em><em>(Ω)</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(Ω)</em><em>=</em><em>Ohm</em>

<em>And </em><em>SI </em><em>unit</em><em> </em><em>of </em><em>current</em><em> </em><em>is</em><em>. </em><em>Ampere(</em><em>Amp)</em><em> </em>

<em><u>hope</u></em><em><u> this</u></em><em><u> helps</u></em><em><u> you</u></em>

<em><u>have</u></em><em><u> a</u></em><em><u> good</u></em><em><u> day</u></em><em><u>.</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em>

8 0
3 years ago
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