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3 years ago

A ball starts at rest and rolls down a ramp, developing a speed of 45 m/s in 7 seconds. Calculate the ball's acceleration.

Physics

1 answer:

Alexxx [7]3 years ago

6 0

Answer:

6.429 m/s^2.

Explanation:

Using equations of motion,

i. vf = vi + at

ii. vf^2 = vi^2 + 2a*S

iii. S = vi*t + 1/2 * (a*t^2)

Where,

vf = final velocity of the motion

vi = initial velocity of the motion

S = distance travelled

t = time taken to complete the motion

a = acceleration due to gravity

Given:

vi = 0m/s

vf = 45 m/s

t = 7 s

a = ?

Using the i. equation of motion,

vf = vi + at

45 = 0 + a*7

a = 45/7

= 6.429 m/s^2

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Answer:

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Explanation:

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3 years ago

Find the velocity (in m/s) of a proton that has a momentum of 4.96 X 10^-19 kg.m/s.

kramer

Answer:

The velocity of the proton is $2.965*10^{8} \frac{m}{s}$

Explanation:

The momentum of a particle is defined as the product of its mass by its velocity and we can calculate it using the following formula:

p=m*v Equation (1)

Where:

p: Is the momentum in kg*m/s

m: Is mass of the particle in kg

v: Is the velocity of the particle in m/s

Data known:

m= 1,6726 × 10^–27 kg : mass of the proton

p= 4.96 X 10^-19 kg.m/s.

We replace this data in the Equation (1):

$4,96*10^{-19} =1.6726*10^{-27} *v$ $v=\frac{4.9*10^{-19} }{1.6726*10^{-27} }$

$v=(\frac{4.96}{1.6726} )*(10^{27-19} )$

$v=2,965*10^{8} m/s$

Answer: The velocity of the proton is $2.965*10^{8} \frac{m}{s}$

3 0

3 years ago

Helppppo please help help I have no time quick I’m in the exam

Sunny_sXe [5.5K]

Answer:

Explanation:

calculate effective resistance of the resistors

= 80 + 120

= 200

overall resistance = 48 ohms

so overall current flowing through circuit

I = V / R

I = 12 / 200

I = 0.06 A

since circuit is in series, current is same at every point so...

potential difference across 80 = R x I

= 80 x 0.06

answer is potential difference = 4.8 V

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3 years ago

Your study buddy claims that an electron always experiences a force in an electric field, but not always in a magnetic field. do

timurjin [86]

It's true charged particles are always acted on by an electric field.when the velocity of the electron is parallel to the magnetic field, the magnetic force vanishes.

4 0

3 years ago

Two protons in a molecule are 4.40 10-10 m apart. Find the electric force exerted by one proton on the other.

Akimi4 [234]

Answer:

F = 1.19 x 10⁹ N

Explanation:

The electrostatic force between the charged particles is given by Colomb's Law as follows:

$F = \frac{kq_{1}q_{2}}{r^{2}}$

where,

F = Electrostatic force = ?

k = Colomb's constant = 9 x 10⁹ N.m²/C²

q₁ = q₂ = charge on proton = 1.6 x 10⁻¹⁹ C

r = distance between protons = 4.4 x 10⁻¹⁰ m

Therefore,

$F = \frac{(9\ x\ 10^{9}\ Nm^{2}/C^{2})(1.6\ x\ 10^{-19}\ C)(1.6\ x\ 10^{-19}\ C)}{(4.4\ x\ 10^{-10})^{2}} \\\\$

8 0

3 years ago