The force exerted by one plate for two parallel plates arrangement is F = QE/2.
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Force one plate exerts on the other</h3>
The force exerted by one plate for two parallel plates arrangement is given as follows;
F = QE/2
where;
- Q is the charge on one plates
- E is the electric field due to the charge
- F is force exerted by one plate
Thus, the force exerted by one plate for two parallel plates arrangement is F = QE/2.
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Answer
Given,
Periscope uses 45-45-90 prisms with total internal reflection adjacent to 45°.
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