Question

A university claims that 80% of its basketball players get degrees. An investigation examines the fate of all 20 players who entered the program over a period of several years that ended six years ago. Of these players, 11 graduated and the remaining 9 are no longer in school. If the university's claim is true, the number of players among the 20 who graduated should have the binomial distribution with n = 20 and p = 0.8. Use the binomial probability formula to answer the question, What is the probability that not all of the 20 graduate?

Answer 1

Answer:

The probability of not all players graduate in approximately 0.988.

Step-by-step explanation:

Let's define,

$X$ = "Number of players that graduated"

We know that $X \sim Bin(20;0.8)$ and the probability density function for a binomial random variable is:

$P(X = k) = {20 \choose k}(0.8)^k(0.2)^{20-k}$, with $k \leq 20$

We want to know the probability that not all of the 20 graduate, in other words we want to know the probability of $P(X < 20)$.

$P(X < 20) = 1 - P(X = 20) =\\= 1 - {20 \choose 20}(0.8)^{20}(0.2)^0 =\\= 1 - 0.8^{20} \approx 0.988$