Question

Given 2.14g of B2H6

Answer 1

Answer:

(A) is 0.0773 mol B2H6

(C) is 2.79 x 10^23 H atoms

Explanation:

Questions (A) and (B) are the same.

2.14 g B2H6 x (1 mol B2H6/27.668g B2H6) = 0.0773 mol B2H6 (A)

27.668 is the molar mass of B2H6 calculated from the period table:

(2 x 10.81) + (6 x 1.008) = 27.668

1.008 is the mass of H and 10.81 is the mass of B

(C)

0.0773 mol B2H6 x (6 mol H/ 1 mol B2H6) x (6.022 x 10^23 H atoms/1 mol H)

= 2.79 x 10^23 hydrogen atoms

Further Explanation:

• For every 1 mol of B2H6, there are 6 moles of H (indicated by the subscript)

• 6.022 x 10^23 is Avogrado's number and it equals to 1 mol of anything

• Avogrado's number can be in units of atoms, molecules, or particles